如何将一本字典与另一本字典的一部分进行比较？

Question

我正在检查 CS50 的 pset6 dna。我在程序的最后一部分遇到问题，我将字典与字典列表的一部分进行比较。

代码：

import csv
import sys


#ensure csv input file
if len(sys.argv) != 3:
    sys.exit("Include csv and txt file")

dna=[]
#open and read csv
file = open(sys.argv[1],"r")
reader = csv.DictReader(file)
for row in reader:
    dna.append(row)

sequence = ""
#open and read txt
file = open(sys.argv[2], "r")
sequence = file.read()

str_list = []
str_list = reader.fieldnames[1:]
seq_count_list = []
seq_count = 0
seq_master_list = {}

#count consecutive STR in sequence
for STR in str_list:
    STR_original = STR
    str_length = len(STR)
    while STR in sequence:
        seq_count += 1
        STR += STR_original
        seq_count_list.append(seq_count)
    seq_master_list[STR[0:str_length]] = str(seq_count)
    seq_count = 0

#unsure how to use this list of names
dna_names = []
for i in dna:
    dna_names.append(i['name'])

#check if sequence matches anyone in dna csv
for row in dna:
    print(row)
    if seq_master_list in row:
        print("FOUND")
    

print(seq_master_list)

具体代码：

for row in dna:
    print(row)
    if seq_master_list in row:
        print("FOUND")

它试图匹配字典 seq_master_list:

{'AGATC': '22', 'TTTTTTCT': '33', 'AATG': '43', 'TCTAG': '12', 'GATA': '26', 'TATC': '18', 'GAAA': '47', 'TCTG': '41'}

字典列表 dna 看起来像：

[
...
{
'name': 'Kingsley', 'AGATC': '7', 'TTTTTTCT': '11', 'AATG': '18', 'TCTAG': '33', 'GATA': '39', 'TATC': '31', 'GAAA': '23', 'TCTG': '14'
},
{
'name': 'Lavender', 'AGATC': '22', 'TTTTTTCT': '33', 'AATG': '43', 'TCTAG': '12', 'GATA': '26', 'TATC': '18', 'GAAA': '47', 'TCTG': '41'
},
{
'name': 'Lily', 'AGATC': '42', 'TTTTTTCT': '47', 'AATG': '48', 'TCTAG': '18', 'GATA': '35', 'TATC': '46', 'GAAA': '48', 'TCTG': '50'
},
...
]

现在我收到错误：

TypeError: unhashable type: 'dict'

我希望它吐出 'name'，在本例中为 'Lavender'。

编辑：

根据来自 JohnGordon 的 Inline Link。

for row in dna:
    print(row)
    if seq_master_list.items() in row.items():
        print("FOUND")

我没有收到任何错误...但似乎没有（没有打印出“FOUND”）

感谢 Chris Charley 的解决方案

Answer 1

for STR in str_list:
    STR_original = STR #I think this part should be changed. Why did you indicate STR_original and use STR below line? 
    str_length = len(STR)
    while STR in sequence:
        seq_count += 1
        STR += STR_original
        seq_count_list.append(seq_count)
    seq_master_list[STR[0:str_length]] = str(seq_count)
    seq_count = 0

Answer 2

要让字典比较相等，您需要从 row 字典中获取 name 键和值。如果 'name' 键和值仍在 row 字典中，它永远不会 == seq_master_list 字典中。

found = False
for row in dna:
    name = row.pop('name') # remove this from the 'row' dict and save the name
    if row == seq_master_list:
        found = True
        print(name)
        break

if not found:
    print('no match')

如何将一本字典与另一本字典的一部分进行比较？

How to compare one dictionary to part of another dictionary?

python

cs50