Python 回复：如何匹配任何数字，即使是带有逗号和小数的数字？

Question

我想匹配任何包含小数、逗号或整数的数字。我尝试了下面的方法，但如果数字有 > 2 个逗号，我的正则表达式将无法匹配。

谢谢

import re

string1= "6,111,123,999 5,450,900 10.32 OCT21  Dec 31, 2019"

num=re.findall(r'\b\d+[.,]*\d+[,]*d*\b', string1)

Result:

['6,111,123', '999', '5,450,900', '10.32', '31', '2019']

Desired Outcome --> ['6,111,123,999', '5,450,900', '10.32', '31', '2019']

Answer 1

尝试(?:[\d]+[.,]?\b)+

它匹配任何可能包含小数、逗号或简单的整数的数字

代码：

import re

string1= "6,111,123,999 5,450,900 10.32 OCT21  Dec 31, 2019"
num = re.findall(r'(?:\b[\d]+[.,]?\b)+', string1)

print(num)

输出：

['6,111,123,999', '5,450,900', '10.32', '31', '2019']

Regex101 Demo

告诉我是否适合你...

Answer 2

匹配所有数字

你可以使用 \d(?:[\d,.]*\d+)?

string1= "6,111,123,999 5,450,900 10.32 OCT21  Dec 31, 2019 1"

import re
re.findall(r'\d(?:[\d,.]*\d+)?', string1)

输出：['6,111,123,999', '5,450,900', '10.32', '21', '31', '2019', '1']

仅匹配独立单词的数字

使用\b[\d,.]*\d+\b:

string1= "6,111,123,999 5,450,900 10.32 OCT21  Dec 31, 2019 1"

import re
re.findall(r'\b[\d,.]*\d+\b', string1)

输出：['6,111,123,999', '5,450,900', '10.32', '31', '2019', '1']

编辑：仅匹配 space、字符串结尾或逗号作为分隔符

string1= "6,111,123,999 5,450,900 10.32 1a2 1-2 OCT21  Dec 31, 2019 1"

import re
re.findall(r'(?:(?<=^)|(?<=\s))[\d,.]*\d+(?=$|\s|,)', string1)

输出：['6,111,123,999', '5,450,900', '10.32', '31', '2019', '1']

Answer 3

这里是我对你想要的结果的快速修复，它是正则表达式（我发现它会产生很多代码噪音）和一些简单的对象操作的混合体。不是很全面，但确实如此：

import re

string_one = "6,111,123,999 5,450,900 10.32 OCT21  Dec 31, 2019"

num=[re.findall(r'^[0-9,.]+', el.rstrip(',')) for el in string_one.split()]

# give a proper result
result = [item for sublist in num for item in sublist]

print(result)
# ['6,111,123,999', '5,450,900', '10.32', '31', '2019']

Python 回复：如何匹配任何数字，即使是带有逗号和小数的数字？

Python re: How to match any numbers even those with comma & decimal?

python

python-re

匹配所有数字

仅匹配独立单词的数字

编辑：仅匹配 space、字符串结尾或逗号作为分隔符