(Mongodb) 获取错误 (BadValue) $in needs an array , when using $map aggregate function
(Mongodb) Getting an error (BadValue) $in needs an array , when using $map aggregate function
我正在尝试使用 map 函数将 字符串数组 转换为 ObjectId 数组,map 将 return 我 ObjectId 数组 我在 $match 中使用它来检查 _id 是否与使用 $in 运算符的数组中存在的任何 objectid 匹配。
数据库配置为
db={
"students": [
{
"_id": ObjectId("5c1a79f7c98da061141475b7"),
"firstName": "Ibrahim",
"kelasID": ObjectId("5c429f9906f2a805bc6cd494"),
"lastName": "Ali",
"schoolID": ObjectId("5c1a735fc98da061141475a1"),
"year": 2018,
"__v": 0,
"addedOn": ISODate("2018-12-25T04:27:47.909Z"),
"checkIn": false,
"checkInStatus": 1,
"contactNo1": "012225656",
"father": "Ali",
"fatherID": "8852245",
"idType": 0,
"lastModified": ISODate("2018-12-25T04:27:47.909Z"),
"mother": "",
"motherID": ""
},
{
"_id": ObjectId("5c3bfea37774fb0b55000cb5"),
"idType": 0,
"checkIn": false,
"checkInStatus": 1,
"year": 2019,
"schoolID": ObjectId("5c1a735fc98da061141475a1"),
"kelasID": ObjectId("5c1a7534c98da061141475a3"),
"firstName": "Umar",
"lastName": "Bin Al-Khattab",
"contactNo1": "601222",
"status": 1,
"addedOn": ISODate("2019-01-14T03:14:43.597Z"),
"lastModified": ISODate("2019-01-14T03:14:43.597Z"),
"__v": 0
},
{
"_id": ObjectId("5c1a7c69c98da061141475bb"),
"idType": 0,
"checkIn": false,
"checkInStatus": 1,
"year": 2018,
"schoolID": ObjectId("5c1a735fc98da061141475a1"),
"kelasID": ObjectId("5c1a7540c98da061141475a5"),
"firstName": "Abdul Rahman",
"lastName": "Affan",
"father": "Affan",
"fatherID": "54321",
"contactNo1": "602288",
"status": 1,
"addedOn": ISODate("2018-12-25T04:30:16.130Z"),
"lastModified": ISODate("2018-12-25T04:30:16.130Z"),
"__v": 0
}
]
}
查询是
db.students.aggregate([
{
"$match": {
"_id": {
$in: {
"stud": {
"$map": {
"input": [
"5c1a79f7c98da061141475b7",
"5c3bfea37774fb0b55000cb5",
"5c1a7c69c98da061141475bb",
"5c3bfea37774fb0b55000cb4",
"5c1a7d32c98da061141475be",
"5c3bfea37774fb0b55000cb7"
],
"in": {
"$toObjectId": "$$this"
}
}
}
}
}
}
}
])
您也可以在这里查看 - https://mongoplayground.net/p/8tQFHxtrttW
上面的方法不起作用,但如果我像下面这样更改查询,它就会起作用。
db.students.aggregate([
{
"$match": {
"_id": {
$in: [
ObjectId("5c1a79f7c98da061141475b7"),
ObjectId("5c3bfea37774fb0b55000cb5")
]
}
}
}
])
Link 到上面的查询- https://mongoplayground.net/p/cjq77KIAcPE
我收到错误 - 查询失败:(BadValue) $in 需要一个数组
任何人都可以帮助解决错误的原因,因为根据 docs map return 一个数组,所以我做错了什么?
不确定为什么它不起作用可能与 $in operator and $in aggregation. When you use an array that is defined by a variable you can use $in operator but when you are using aggregation result ( in this case $map ) you have to use $in aggregation. But to use $in aggregation 有关,您需要使用 $expr 来获得 $match。
您可以试试下面的代码,效果很好
db.students.aggregate([
{
$addFields: {
studentIds: {
$map: {
input: [
"5c1a79f7c98da061141475b7",
"5c3bfea37774fb0b55000cb5",
"5c1a7c69c98da061141475bb",
"5c3bfea37774fb0b55000cb4",
"5c1a7d32c98da061141475be",
"5c3bfea37774fb0b55000cb7",
],
in: {
$toObjectId: "$$this",
},
},
},
},
},
{
$match: {
$expr: {
$in: ["$_id", "$studentIds"],
},
},
},
]);
或者如果你想结合这两个阶段,你可以这样做
db.students.aggregate([
{
$match: {
$expr: {
$in: [
"$_id",
{
$map: {
input: [
"5c1a79f7c98da061141475b7",
"5c3bfea37774fb0b55000cb5",
"5c1a7c69c98da061141475bb",
"5c3bfea37774fb0b55000cb4",
"5c1a7d32c98da061141475be",
"5c3bfea37774fb0b55000cb7",
],
in: {
$toObjectId: "$$this",
},
},
},
],
},
},
},
]);
我正在尝试使用 map 函数将 字符串数组 转换为 ObjectId 数组,map 将 return 我 ObjectId 数组 我在 $match 中使用它来检查 _id 是否与使用 $in 运算符的数组中存在的任何 objectid 匹配。
数据库配置为
db={
"students": [
{
"_id": ObjectId("5c1a79f7c98da061141475b7"),
"firstName": "Ibrahim",
"kelasID": ObjectId("5c429f9906f2a805bc6cd494"),
"lastName": "Ali",
"schoolID": ObjectId("5c1a735fc98da061141475a1"),
"year": 2018,
"__v": 0,
"addedOn": ISODate("2018-12-25T04:27:47.909Z"),
"checkIn": false,
"checkInStatus": 1,
"contactNo1": "012225656",
"father": "Ali",
"fatherID": "8852245",
"idType": 0,
"lastModified": ISODate("2018-12-25T04:27:47.909Z"),
"mother": "",
"motherID": ""
},
{
"_id": ObjectId("5c3bfea37774fb0b55000cb5"),
"idType": 0,
"checkIn": false,
"checkInStatus": 1,
"year": 2019,
"schoolID": ObjectId("5c1a735fc98da061141475a1"),
"kelasID": ObjectId("5c1a7534c98da061141475a3"),
"firstName": "Umar",
"lastName": "Bin Al-Khattab",
"contactNo1": "601222",
"status": 1,
"addedOn": ISODate("2019-01-14T03:14:43.597Z"),
"lastModified": ISODate("2019-01-14T03:14:43.597Z"),
"__v": 0
},
{
"_id": ObjectId("5c1a7c69c98da061141475bb"),
"idType": 0,
"checkIn": false,
"checkInStatus": 1,
"year": 2018,
"schoolID": ObjectId("5c1a735fc98da061141475a1"),
"kelasID": ObjectId("5c1a7540c98da061141475a5"),
"firstName": "Abdul Rahman",
"lastName": "Affan",
"father": "Affan",
"fatherID": "54321",
"contactNo1": "602288",
"status": 1,
"addedOn": ISODate("2018-12-25T04:30:16.130Z"),
"lastModified": ISODate("2018-12-25T04:30:16.130Z"),
"__v": 0
}
]
}
查询是
db.students.aggregate([
{
"$match": {
"_id": {
$in: {
"stud": {
"$map": {
"input": [
"5c1a79f7c98da061141475b7",
"5c3bfea37774fb0b55000cb5",
"5c1a7c69c98da061141475bb",
"5c3bfea37774fb0b55000cb4",
"5c1a7d32c98da061141475be",
"5c3bfea37774fb0b55000cb7"
],
"in": {
"$toObjectId": "$$this"
}
}
}
}
}
}
}
])
您也可以在这里查看 - https://mongoplayground.net/p/8tQFHxtrttW 上面的方法不起作用,但如果我像下面这样更改查询,它就会起作用。
db.students.aggregate([
{
"$match": {
"_id": {
$in: [
ObjectId("5c1a79f7c98da061141475b7"),
ObjectId("5c3bfea37774fb0b55000cb5")
]
}
}
}
])
Link 到上面的查询- https://mongoplayground.net/p/cjq77KIAcPE
我收到错误 - 查询失败:(BadValue) $in 需要一个数组 任何人都可以帮助解决错误的原因,因为根据 docs map return 一个数组,所以我做错了什么?
不确定为什么它不起作用可能与 $in operator and $in aggregation. When you use an array that is defined by a variable you can use $in operator but when you are using aggregation result ( in this case $map ) you have to use $in aggregation. But to use $in aggregation 有关,您需要使用 $expr 来获得 $match。
您可以试试下面的代码,效果很好
db.students.aggregate([
{
$addFields: {
studentIds: {
$map: {
input: [
"5c1a79f7c98da061141475b7",
"5c3bfea37774fb0b55000cb5",
"5c1a7c69c98da061141475bb",
"5c3bfea37774fb0b55000cb4",
"5c1a7d32c98da061141475be",
"5c3bfea37774fb0b55000cb7",
],
in: {
$toObjectId: "$$this",
},
},
},
},
},
{
$match: {
$expr: {
$in: ["$_id", "$studentIds"],
},
},
},
]);
或者如果你想结合这两个阶段,你可以这样做
db.students.aggregate([
{
$match: {
$expr: {
$in: [
"$_id",
{
$map: {
input: [
"5c1a79f7c98da061141475b7",
"5c3bfea37774fb0b55000cb5",
"5c1a7c69c98da061141475bb",
"5c3bfea37774fb0b55000cb4",
"5c1a7d32c98da061141475be",
"5c3bfea37774fb0b55000cb7",
],
in: {
$toObjectId: "$$this",
},
},
},
],
},
},
},
]);