将 JSON 反序列化为具有通用类型参数的接口列表
Deserialization of JSON to List of Interface with generic type parameter
如标题所述,我正在尝试反序列化 JSON 但遇到了一些麻烦。我认为下面包含了必要的信息。
public class Variable<T> : IVariable where T : IConvertible
{
//...
}
public class ArrayVariable<T> : IVariable where T : IConvertible
{
//...
}
所以我有一个 IVariable 列表,然后我成功序列化了它(所有信息都在 json 中):
JsonConvert.SerializeObject(myIVariableList)
现在我正在尝试反序列化它,但我无法确定正确的方法来进行反序列化,因为它涉及查找通用类型 T
除了类型 Variable
或 ArrayVariable
。我已经试过了
JsonConvert.DeserializeObject<List<IVariable>>(result.newValues)
但显然,您可以创建接口的实例。任何帮助将不胜感激。
您可以使用 TypeNameHandling.All
将类型信息添加到您的序列化 json 中,然后在解析过程中使用它:
var variables = new List<IVariable>()
{
new Variable<int>()
};
var settings = new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.All };
var serializeObject = JsonConvert.SerializeObject(variables, settings);
var list = JsonConvert.DeserializeObject<List<IVariable>>(serializeObject, settings);
您可以使用 TypeNameHandling.All
,但我强烈建议您避免使用它,因为它是 。
另一个更安全的选择是使用自定义转换器。这是一个非常简单(且脆弱)的示例,应该可以帮助您入门:
首先让我们做一些共享接口的基本 类:
public interface IVariable { }
public class Foo : IVariable
{
public int A { get; set; }
}
public class Bar : IVariable
{
public int B { get; set; }
}
现在我们可以制作转换器了:
public class IVariableConverter : JsonConverter<IVariable>
{
public override IVariable ReadJson(JsonReader reader, Type objectType,
IVariable existingValue, bool hasExistingValue, JsonSerializer serializer)
{
// First load the JSON into a JObject
var variable = JObject.Load(reader);
// If the JSON had a property called A, it must be a Foo:
if (variable.ContainsKey("A"))
{
return variable.ToObject<Foo>();
}
// If the JSON had a property called B, it must be a Bar:
if (variable.ContainsKey("B"))
{
return variable.ToObject<Bar>();
}
// And who knows what was passed in if it was missing both of those properties?!
throw new Exception("Er, no idea what that JSON was supposed to be!");
}
public override void WriteJson(JsonWriter writer, IVariable value,
JsonSerializer serializer)
{
// Feel free to write your own code here if you need it
throw new NotImplementedException();
}
}
现在我们可以做一些实际的反序列化了:
// A basic JSON example:
var json = "[{\"A\":1},{\"B\":2}]";
// The settings to tell the serialiser how to process an IVariable object
var settings = new JsonSerializerSettings
{
Converters = new List<JsonConverter> { new IVariableConverter() }
};
// And deserialise with the defined settings
var result = JsonConvert.DeserializeObject<List<IVariable>>(json, settings);
您需要在如何识别每种类型方面更有创意,但这是实现您需要的安全方法。
如标题所述,我正在尝试反序列化 JSON 但遇到了一些麻烦。我认为下面包含了必要的信息。
public class Variable<T> : IVariable where T : IConvertible
{
//...
}
public class ArrayVariable<T> : IVariable where T : IConvertible
{
//...
}
所以我有一个 IVariable 列表,然后我成功序列化了它(所有信息都在 json 中):
JsonConvert.SerializeObject(myIVariableList)
现在我正在尝试反序列化它,但我无法确定正确的方法来进行反序列化,因为它涉及查找通用类型 T
除了类型 Variable
或 ArrayVariable
。我已经试过了
JsonConvert.DeserializeObject<List<IVariable>>(result.newValues)
但显然,您可以创建接口的实例。任何帮助将不胜感激。
您可以使用 TypeNameHandling.All
将类型信息添加到您的序列化 json 中,然后在解析过程中使用它:
var variables = new List<IVariable>()
{
new Variable<int>()
};
var settings = new JsonSerializerSettings { TypeNameHandling = TypeNameHandling.All };
var serializeObject = JsonConvert.SerializeObject(variables, settings);
var list = JsonConvert.DeserializeObject<List<IVariable>>(serializeObject, settings);
您可以使用 TypeNameHandling.All
,但我强烈建议您避免使用它,因为它是
另一个更安全的选择是使用自定义转换器。这是一个非常简单(且脆弱)的示例,应该可以帮助您入门:
首先让我们做一些共享接口的基本 类:
public interface IVariable { }
public class Foo : IVariable
{
public int A { get; set; }
}
public class Bar : IVariable
{
public int B { get; set; }
}
现在我们可以制作转换器了:
public class IVariableConverter : JsonConverter<IVariable>
{
public override IVariable ReadJson(JsonReader reader, Type objectType,
IVariable existingValue, bool hasExistingValue, JsonSerializer serializer)
{
// First load the JSON into a JObject
var variable = JObject.Load(reader);
// If the JSON had a property called A, it must be a Foo:
if (variable.ContainsKey("A"))
{
return variable.ToObject<Foo>();
}
// If the JSON had a property called B, it must be a Bar:
if (variable.ContainsKey("B"))
{
return variable.ToObject<Bar>();
}
// And who knows what was passed in if it was missing both of those properties?!
throw new Exception("Er, no idea what that JSON was supposed to be!");
}
public override void WriteJson(JsonWriter writer, IVariable value,
JsonSerializer serializer)
{
// Feel free to write your own code here if you need it
throw new NotImplementedException();
}
}
现在我们可以做一些实际的反序列化了:
// A basic JSON example:
var json = "[{\"A\":1},{\"B\":2}]";
// The settings to tell the serialiser how to process an IVariable object
var settings = new JsonSerializerSettings
{
Converters = new List<JsonConverter> { new IVariableConverter() }
};
// And deserialise with the defined settings
var result = JsonConvert.DeserializeObject<List<IVariable>>(json, settings);
您需要在如何识别每种类型方面更有创意,但这是实现您需要的安全方法。