如何读取 Pandas 中未正确分隔的 .txt

Question

我有一个 .txt 文件，它与 .csv 非常相似，但又不完全相同。如您所见，前 4 列可以用 space 分隔，但最后一个字符串将分成不同数量的列。我需要最后一个字符串只是一列。

09 4 10/11/2021 22:21:17 The PLC reported that sorter SS02 has E-stopped.
08 4 10/11/2021 22:21:17 The PLC reported that sorter SS02 has stopped.
08 4 10/11/2021 22:21:18 The PLC reported that sorter SS01 has stopped.
20 5 10/11/2021 22:21:18 The PLC reported that purge mode was disabled for sorter SS02.
20 5 10/11/2021 22:21:18 The PLC reported that purge mode was disabled for sorter SS01.
23 5 10/11/2021 22:21:19 AUX Sortation has been enabled for sorter SS02.
23 5 10/11/2021 22:21:20 AUX Sortation has been enabled for sorter SS01.

我怎样才能读到这个，所以我只有 5 个一致的列？稍后我可能会将日期和时间合并为一栏。

Answer 1

您可以预先解析每一行，然后创建 DataFrame，例如：

import pandas as pd

with open('input.txt') as f_input:
    data = [line.strip().split(' ', 4) for line in f_input]
        
df = pd.DataFrame(data, columns=['c1', 'c2', 'date', 'time', 'desc'])
print(df)

给你：

   c1 c2        date      time                                                            desc
0  09  4  10/11/2021  22:21:17                The PLC reported that sorter SS02 has E-stopped.
1  08  4  10/11/2021  22:21:17                  The PLC reported that sorter SS02 has stopped.
2  08  4  10/11/2021  22:21:18                  The PLC reported that sorter SS01 has stopped.
3  20  5  10/11/2021  22:21:18  The PLC reported that purge mode was disabled for sorter SS02.
4  20  5  10/11/2021  22:21:18  The PLC reported that purge mode was disabled for sorter SS01.
5  23  5  10/11/2021  22:21:19                 AUX Sortation has been enabled for sorter SS02.
6  23  5  10/11/2021  22:21:20                 AUX Sortation has been enabled for sorter SS01.

可以通过组合 date 和 time 列并将它们转换为日期时间来添加日期时间列：

df['datetime'] = pd.to_datetime(df['date'] + ' ' + df['time'])

如何读取 Pandas 中未正确分隔的 .txt

How to read a .txt in Pandas that isn't properly delimited

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