使用 context_diff 只打印有差异的行

Question

我有下面的代码打印两个文件之间的差异，我使用了 difflib 模块中的 context_diff。

import difflib

file1 = open(“filename1.json”,”r”)
file2 = open(“filename2.json”,”r”)

diff = difflib.context_diff(file1.readLines(), file2.readLines())
delta = ‘’.join(diff)
print(delta)

filename1.json

{ 
“Name” : “John”,
“Occupation” : “Manager”, 
“Age” : 35,
“Company” : “vTech”
}

filename2.json

{ 
“Name” : “Mel”,
“Occupation” : “Developer”, 
“Age” : 35,
“Company” : “vTech”
}

我只想打印有差异的行。无论如何我们可以做到吗？如果是这样请建议。谢谢我提前了。

预期输出：

！ “姓名”：“约翰”，

！ “职业”：“经理”，

！ “姓名”：“梅尔”，

！ “职业”：“开发人员”，

实际产量

！ “姓名”：“约翰”，

！ “职业”：“经理”，

“年龄”：35，

“公司”：“伟易达”

！ “姓名”：“梅尔”，

！ “职业”：“开发人员”，

“年龄”：35，

“公司”：“伟易达”

Answer 1

来自the docs：

 difflib.context_diff(a, b, fromfile='', tofile='', fromfiledate='', tofiledate='', n=3, lineterm='\n')

Context diffs are a compact way of showing just the lines that have changed plus a few lines of context. The changes are shown in a before/after style. The number of context lines is set by n which defaults to three.

尝试将 n 设置为 0 以不显示上下文：

diff = difflib.context_diff(file1.readLines(), file2.readLines(), n=0)

使用 context_diff 只打印有差异的行

Using context_diff print only lines which have differences

python

difflib