如何根据深度嵌套的键对嵌套字典列表进行排序？

Question

我有一个如下所示的列表：

ls = [
    {
        "max_supply": None,
        "platform": None,
        "quote": {
            "USD": {
                "fully_diluted_market_cap": 464800388135.72,
                "last_updated": "2021-10-20T13:37:02.000Z",
                "market_cap": 464800388135.7246,
                "price": 3938.871641392752,
                "volume_24h": 15411634916.820467,
                "volume_change_24h": -3.4909
            }
        }
    },
    {
        "max_supply": None,
        "platform": None,
        "quote": {
            "USD": {
                "fully_diluted_market_cap": 58764548678.52,
                "last_updated": "2021-10-20T13:37:03.000Z",
                "market_cap": 58764548678.52,
                "price": 4784.77,
                "volume_24h": 189992412916.647,
                "volume_change_24h": 85.422
            }
        }
    },
]

如何按位于 quote 和 USD 键中的每个 market_cap 值对给定列表进行排序？

我找到了一些解决方案，但它们只是指按一级字典键和值排序，但是我还没有找到任何在二级字典中按键和值排序的解决方案深的。在给定列表中。

Answer 1

您可以将 lambda 函数作为内置 sorted 函数的 key 参数传递：

ls = [
    {
        "max_supply": None,
        "platform": None,
        "quote": {
            "USD": {
                "fully_diluted_market_cap": 464800388135.72,
                "last_updated": "2021-10-20T13:37:02.000Z",
                "market_cap": 464800388135.7246,
                "price": 3938.871641392752,
                "volume_24h": 15411634916.820467,
                "volume_change_24h": -3.4909
            }
        }
    },
    {
        "max_supply": None,
        "platform": None,
        "quote": {
            "USD": {
                "fully_diluted_market_cap": 58764548678.52,
                "last_updated": "2021-10-20T13:37:03.000Z",
                "market_cap": 58764548678.52,
                "price": 4784.77,
                "volume_24h": 189992412916.647,
                "volume_change_24h": 85.422
            }
        }
    },
]
sorted_ls = sorted(ls, key=lambda obj: obj["quote"]["USD"]["market_cap"])

或者，如果您想就地编辑列表，您可以使用 .sort() 方法。

Answer 2

您可以定义自己的函数，returns 作为排序依据的键，然后像这样使用 sort

all_data = [
    {
        "max_supply": null,
        "platform": null,
        "quote": {
            "USD": {
                "fully_diluted_market_cap": 464800388135.72,
                "last_updated": "2021-10-20T13:37:02.000Z",
                "market_cap": 464800388135.7246,
                "price": 3938.871641392752,
                "volume_24h": 15411634916.820467,
                "volume_change_24h": -3.4909
            }
        }
    },
    {
        "max_supply": null,
        "platform": null,
        "quote": {
            "USD": {
                "fully_diluted_market_cap": 58764548678.52,
                "last_updated": "2021-10-20T13:37:03.000Z",
                "market_cap": 58764548678.52,
                "price": 4784.77,
                "volume_24h": 189992412916.647,
                "volume_change_24h": 85.422
            }
        }
    },
]

def get_sort_key(current_dict):
    return current_dict['quote']['USD']['market_cap']
all_data.sort(key=get_sort_key)
print(f'Sorted dict: {all_data}')

如何根据深度嵌套的键对嵌套字典列表进行排序？

How to sort a list of nested dictionaries based on a deeply nested key?

python

python-3.9