如何在数组中找到最大值 double

Question

我正在构建一个计算器来计算医用大麻药房的价格。所有销售均需缴纳 16% 的税，并在特定重量下享受价格优惠。我的目标是在给定税收和休息的情况下，为客户找到一个以最佳价格出售的重量。我只想尝试获取双精度列表的最高值，与断点数组进行比较以查看它们是否满足断点的特定阈值。从字面上看，我似乎无法在 weightList 数组中获得最大双倍数。这是我的代码。我的双打 gramPrice、eighthPrice 等是给定断点处的 price/gram。 gramWeight、eighthWeight, 等是计算在该断点接收的产品重量。我猜这是一个草率的术语，但我怎样才能找到我的双数组的最大值？

import java.util.Scanner;
import java.text.DecimalFormat;
public class main {

    public static void main(String[] args) {
        Scanner reader = new Scanner(System.in);
        DecimalFormat df = new DecimalFormat("##.##");
        
        int desiredPrice = 0 , pricePoint = 0;
        int fivePerGram[] = {5, 15, 25, 50, 100};
        int eightPerGram[] = {8, 25, 45, 90, 160};
        double weightFormat[] = {1, 3.5, 7, 14, 28};
        
        System.out.print("Enter Desired Amount OTD: ");
        if(reader.hasNextInt() == true) {
            desiredPrice = reader.nextInt();
        }
        System.out.print("Enter Price Point (3, 5, 8, 10, 12): " );
        if(reader.hasNextInt() == true) {
            pricePoint = reader.nextInt();
        }
        
        if(pricePoint == 8) {
            double gramPrice = (eightPerGram[0]/1)*1.16;gramPrice = Double.parseDouble(df.format(gramPrice));
            double eighthPrice = (eightPerGram[1]/3.5)*1.16;eighthPrice = Double.parseDouble(df.format(eighthPrice));
            double quarterPrice = (eightPerGram[2]/7)*1.16;quarterPrice = Double.parseDouble(df.format(quarterPrice));
            double halfPrice = (eightPerGram[3]/14)*1.16;halfPrice = Double.parseDouble(df.format(halfPrice));
            double ouncePrice = (eightPerGram[4]/28)*1.16;ouncePrice = Double.parseDouble(df.format(ouncePrice));
            
            double gramWeight = desiredPrice/gramPrice;gramWeight = Double.parseDouble(df.format(gramWeight));
            double eighthWeight = desiredPrice/eighthPrice;eighthWeight = Double.parseDouble(df.format(eighthWeight));
            double quarterWeight = desiredPrice/quarterPrice;quarterWeight = Double.parseDouble(df.format(quarterWeight));
            double halfWeight = desiredPrice/halfPrice;halfWeight = Double.parseDouble(df.format(halfWeight));
            double ounceWeight = desiredPrice/ouncePrice;ounceWeight = Double.parseDouble(df.format(ounceWeight));
            
            double weightList[] = {gramWeight, eighthWeight, quarterWeight, halfWeight, ounceWeight};

            
        }
    }
}

Answer 1

请注意，我很确定我明白您要做什么。如果您想要 weightList 数组中的最高值，只需执行以下操作。

标准 Java 8+

final double maxWeight = Arrays.stream(weightList).max().getAsDouble();

与其他图书馆

Apache Commons Lang3 的 NumberUtils

final double maxWeight = NumberUtils.max(weightList);