How to fix phpMyAdmin Fatal error: Uncaught TypeError: mb_strtolower() expects parameter 1 to be string

Question

PhpMyAdmin 在执行查询时导致错误：

SELECT * FROM users u 
    INNER JOIN address a ON u.userid=a.id
    INNER JOIN  health_status h ON u.userid=h.uid
    WHERE u.userid='1634627411'

SELECT * 
from users u 
    INNER join friends f on u.userid=f.user 
    inner join friends f1 on u.userid = f1.friend 
WHERE f.user="1634627411"

两个查询都抛出错误

错误：

Fatal error: Uncaught TypeError: mb_strtolower() expects parameter 1 to be string, null given in /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Display/Results.php:3095 Stack trace: #0 /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Display/Results.php(3095): mb_strtolower(NULL) #1 /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Display/Results.php(2772): PhpMyAdmin\Display\Results->getRowInfoForSpecialLinks(Array, Array) #2 /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Display/Results.php(2613): PhpMyAdmin\Display\Results->getRowValues(Object(mysqli_result), Array, 0, Array, Array, '', Array, 'SELECT * FROM u...', Array) #3 /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Display/Results.php(4219): PhpMyAdmin\Display\Results->getTableBody(Object(mysqli_result), Array, Array, Array, false) #4 /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Sql.php(1364): PhpMyAdmin\Display\Results->getTable(Object(mysqli_result), Array, Array, false) #5 /Application in /Applications/XAMPP/xamppfiles/phpmyadmin/libraries/classes/Display/Results.php on line 3095

我已经尝试过这个问题。

我的 phpmyadmin 版本也是最新的 5.1.1

错误是什么意思，如何解决？

Answer 1

您需要升级 phpMyAdmin 版本。版本 5.1.1 与 PHP 8.1.

不兼容

截至发布时，新版本似乎尚未准备就绪，因此暂时降级至 PHP 8.0。

How to fix phpMyAdmin Fatal error: Uncaught TypeError: mb_strtolower() expects parameter 1 to be string

How to fix phpMyAdmin Fatal error: Uncaught TypeError: mb_strtolower() expects parameter 1 to be string

php

phpmyadmin

php-8.1