Python 导入语句导致代码覆盖失败

Question

我有以下项目结构：

v/b.py
v/e.py
v/e_test.py
v/p.py
v/__init__.py

#v/e.py

from b import B
from p import P

class E(object):
   def run(self): pass

#v/p.py

class P(object):
   def run(self): pass

#v/b.py

from p import P

class B(object):
   def run(self): pass

#v/e_test.py

from e import E
import unittest

class ETest(unittest.Testcase):
   def testSomething(self): pass

if __name__ == '__main__':
    unittest.main()

那我运行这个pip3 install coverage.

然后coverage run e_test.py

它给我这个错误

Traceback (most recent call last):
  File "e_test.py", line 4, in <module>
    from e import E
  File "~/v/e.py", line 1, in <module>
    from b import B
  File "~/v/b.py", line 1, in <module>
    from p import P
ImportError: cannot import name 'P' from 'p' (/Library/Developer/CommandLineTools/Library/Frameworks/Python3.framework/Versions/3.8/lib/python3.8/p.py)

我现在的问题是如何解决这个问题。我也希望能够运行:

覆盖率运行e_test.pyb_test.pyfiles_test.py
python3 e_test.py
python3 e.py

Answer 1

mm，我想 P Class 还没有声明，所以你得到了这样的错误

Answer 2

#v/p.py

class P(object):
   def run(self): pass

你还没有定义P是什么，报错p.py没有P对象

Answer 3

终于找到答案了。如果我在包含 v 文件夹的父文件夹中，我可以运行以下命令。

PYTHONPATH=./v:$PYTHONPATH coverage run -m unittest discover -s v -p "*_test.py"

或无覆盖

PYTHONPATH=./v:$PYTHONPATH python3 -m unittest discover -s v -p "*_test.py"

如果我在 v 文件夹中，我可以运行

python3 e.py

和

python3 e_test.py

Python 导入语句导致代码覆盖失败

Python Code Coverage Failing with import statements

code-coverage

python-3.x