Python 搜索字典值（坐标列表）并将其与列表（bbox）和 return 特定键进行比较

Question

我有一个字典，其值如下（坐标 = [cx1, cx2, cy1, cy2]）：

> co_list =
[
  {
    "data.01": [
      6.9490666,
      47.4897206,
      7.0073678,
      47.5169333
    ]
  },
  {
    "data.02": [
      6.9493157,
      47.4627392,
      7.0075872,
      47.4899521
    ]
  }
]

根据用户输入，我得到了一个包含 4 个坐标的列表 (bbox = [bx1, by1, bx2, by2])

bb_list = [6.974532, 47.469739, 7.000004, 47.481432]

我想检查bb_list是否符合co_list的值，如果左下角或右上角在一定范围内，则返回相应的键。我如何在 co_list 的每个 value/values 上迭代 bb_list 的值，并且应该通过类似的方式比较它们：

if bx1 >= cx1 and <= cx2 and if by1 >= cy1 and <= cy2 or if bx2 >= cx1 and <= cx2 and if by2 <= cy2 and >= cy1

欢迎任何帮助，谢谢！

Answer 1

这个怎么样。

代码

co_list = [
  {
    "data.01": [
      6.9490666,
      47.4897206,
      7.0073678,
      47.5169333
    ]
  },
  {
    "data.02": [
      6.9493157,
      47.4627392,
      7.0075872,
      47.4899521
    ]
  }
]

bb_list = [6.974532, 47.469739, 7.000004, 47.481432]

# Loop thru the list
for c in co_list:
    # Loop thru dict
    for k, v in c.items():
        cx1 = v[0]
        cx2 = v[1]
        cy1 = v[2]
        cy2 = v[3]

        # take the element of a list
        bx1 = bb_list[0]
        by1 = bb_list[1]
        bx2 = bb_list[2]
        by2 = bb_list[3]

        if (bx1 >= cx1 and bx1 <= cx2 and by1 >= cy1 and by1 <= cy2 
            or bx2 >= cx1 and bx2 <= cx2 and by2 <= cy2 and by2 >= cy1):
            print(k)

输出

data.01
data.02

Python 搜索字典值（坐标列表）并将其与列表（bbox）和 return 特定键进行比较

Python search and compare Dict-values (coordinates-list) to a list (bbox) and return specific key

python

dictionary

loops

compare

list

代码

输出