等待()通过克隆创建的线程?
wait() for thread made via clone?
我打算将其重写为程序集,这样我就不能使用 c 或 c++ 标准库了。下面的代码运行完美。但是我想要一个线程而不是第二个进程。如果您在第 25 行取消注释 /*CLONE_THREAD|*/
,waitpid
将 return -1。我想要一个阻塞函数,当我的线程完成时它会恢复。我无法通过查看手册页弄清楚它希望我做什么
#include <sys/wait.h>
#include <sched.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/mman.h>
int globalValue=0;
static int childFunc(void*arg)
{
printf("Global value is %d\n", globalValue);
globalValue += *(int*)&arg;
return 31;
}
int main(int argc, char *argv[])
{
auto stack_size = 1024 * 1024;
auto stack = (char*)mmap(NULL, stack_size, PROT_READ | PROT_WRITE, MAP_PRIVATE | MAP_ANONYMOUS | MAP_STACK, -1, 0);
if (stack == MAP_FAILED) { perror("mmap"); exit(EXIT_FAILURE); }
globalValue = 5;
auto pid = clone(childFunc, stack + stack_size, /*CLONE_THREAD|*/CLONE_VM|CLONE_SIGHAND|SIGCHLD, (void*)7);
sleep(1); //So main and child printf don't collide
if (pid == -1) { perror("clone"); exit(EXIT_FAILURE); }
printf("clone() returned %d\n", pid);
int status;
int waitVal = waitpid(-1, &status, __WALL);
printf("Expecting 12 got %d. Expecting 31 got %d. ID=%d\n", globalValue, WEXITSTATUS(status), waitVal);
return 0;
}
如果你想用线程异步调用函数,我建议使用 std::async。这里的例子:
#include <iostream>
#include <future>
#include <mutex>
#include <condition_variable>
int globalValue = 0; // could also have been std::atomic<int> but I choose a mutex (to also serialize output to std::cout)
std::mutex mtx; // to protect access to data in multithreaded applications you can use mutexes
int childFunc(const int value)
{
std::unique_lock<std::mutex> lock(mtx);
globalValue = value;
std::cout << "Global value set to " << globalValue << "\n";
return 31;
}
int getValue()
{
std::unique_lock<std::mutex> lock(mtx);
return globalValue;
}
int main(int argc, char* argv[])
{
// shared memory stuff is not needed for threads
// launch childFunc asynchronously
// using a lambda function : https://en.cppreference.com/w/cpp/language/lambda
// to call a function asynchronously : https://en.cppreference.com/w/cpp/thread/async
// note I didn't ues the C++ thread class, it can launch things asynchronously
// however async is both a better abstraction and you can return values (and exceptions)
// to the calling thread if you need to (which you do in this case)
std::future<int> future = std::async(std::launch::async, []
{
return childFunc(12);
});
// wait until asynchronous function call is complete
// and get its return value;
int value_from_async = future.get();
std::cout << "Expected global value 12, value = " << getValue() << "\n";
std::cout << "Expected return value from asynchronous process is 31, value = " << value_from_async << "\n";
return 0;
}
我打算将其重写为程序集,这样我就不能使用 c 或 c++ 标准库了。下面的代码运行完美。但是我想要一个线程而不是第二个进程。如果您在第 25 行取消注释 /*CLONE_THREAD|*/
,waitpid
将 return -1。我想要一个阻塞函数,当我的线程完成时它会恢复。我无法通过查看手册页弄清楚它希望我做什么
#include <sys/wait.h>
#include <sched.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/mman.h>
int globalValue=0;
static int childFunc(void*arg)
{
printf("Global value is %d\n", globalValue);
globalValue += *(int*)&arg;
return 31;
}
int main(int argc, char *argv[])
{
auto stack_size = 1024 * 1024;
auto stack = (char*)mmap(NULL, stack_size, PROT_READ | PROT_WRITE, MAP_PRIVATE | MAP_ANONYMOUS | MAP_STACK, -1, 0);
if (stack == MAP_FAILED) { perror("mmap"); exit(EXIT_FAILURE); }
globalValue = 5;
auto pid = clone(childFunc, stack + stack_size, /*CLONE_THREAD|*/CLONE_VM|CLONE_SIGHAND|SIGCHLD, (void*)7);
sleep(1); //So main and child printf don't collide
if (pid == -1) { perror("clone"); exit(EXIT_FAILURE); }
printf("clone() returned %d\n", pid);
int status;
int waitVal = waitpid(-1, &status, __WALL);
printf("Expecting 12 got %d. Expecting 31 got %d. ID=%d\n", globalValue, WEXITSTATUS(status), waitVal);
return 0;
}
如果你想用线程异步调用函数,我建议使用 std::async。这里的例子:
#include <iostream>
#include <future>
#include <mutex>
#include <condition_variable>
int globalValue = 0; // could also have been std::atomic<int> but I choose a mutex (to also serialize output to std::cout)
std::mutex mtx; // to protect access to data in multithreaded applications you can use mutexes
int childFunc(const int value)
{
std::unique_lock<std::mutex> lock(mtx);
globalValue = value;
std::cout << "Global value set to " << globalValue << "\n";
return 31;
}
int getValue()
{
std::unique_lock<std::mutex> lock(mtx);
return globalValue;
}
int main(int argc, char* argv[])
{
// shared memory stuff is not needed for threads
// launch childFunc asynchronously
// using a lambda function : https://en.cppreference.com/w/cpp/language/lambda
// to call a function asynchronously : https://en.cppreference.com/w/cpp/thread/async
// note I didn't ues the C++ thread class, it can launch things asynchronously
// however async is both a better abstraction and you can return values (and exceptions)
// to the calling thread if you need to (which you do in this case)
std::future<int> future = std::async(std::launch::async, []
{
return childFunc(12);
});
// wait until asynchronous function call is complete
// and get its return value;
int value_from_async = future.get();
std::cout << "Expected global value 12, value = " << getValue() << "\n";
std::cout << "Expected return value from asynchronous process is 31, value = " << value_from_async << "\n";
return 0;
}