在 javascript 中不使用内置函数逐字反转字符串
Revers a string word by word without using inbuilt function in javascript
function reverse1(str) {
let r = "";
for (let i = str.length - 1; i >= 0; i--) {
r += str[i];
}
return r;
}
console.log(reverse1("I like this program very much"));
output: // hcum yrev margorp siht ekil I
but expected output: I ekil siht margorp yrev hcum
please can any one answer this....???
遍历原字符串,将单个单词反转
function reverseUtil(str) {
let r = "";
for (let i = str.length - 1; i >=0; i--) {
r += str[i];
}
return r;
}
function reverse1(str) {
let r = "", tmp = "";
for (let i = 0; i < str.length; i++) {
if (str[i] == ' ') {
r += reverseUtil(tmp) + ' ';
tmp = "";
} else tmp += str[i];
}
// last word
r += reverseUtil(tmp);
return r;
}
console.log(reverse1("I like this program very much"));
你正在反转整个字符串。如果要使用单个函数并假设字符串仅包含 spaces,则可以遍历字符串的每个字符。
如果您遇到 space,您可以将其附加到结果中。如果您遇到另一个字符,您可以将其添加到一个临时字符串中以构建该单词的反向版本。
然后,当下一个字符是 space 或迭代中的最后一个字符时,将单词的反转版本附加到结果中。
function reverse1(str) {
let result = "", tmp = "";
for (let i = 0; i < str.length; i++) {
if (str[i] === ' ') {
result += ' '; continue;
}
tmp = str[i] + tmp;
if (str[i + 1] === undefined || str[i + 1] === ' ') {
result += tmp; tmp = "";
}
}
return result;
}
console.log(reverse1("I like this program very much"));
console.log(reverse1(" I like this program very much "));
console.log(reverse1("abc"));
function reverse1(str) {
let r = "";
for (let i = str.length - 1; i >= 0; i--) {
r += str[i];
}
return r;
}
console.log(reverse1("I like this program very much"));
output: // hcum yrev margorp siht ekil I
but expected output: I ekil siht margorp yrev hcum
please can any one answer this....???
遍历原字符串,将单个单词反转
function reverseUtil(str) {
let r = "";
for (let i = str.length - 1; i >=0; i--) {
r += str[i];
}
return r;
}
function reverse1(str) {
let r = "", tmp = "";
for (let i = 0; i < str.length; i++) {
if (str[i] == ' ') {
r += reverseUtil(tmp) + ' ';
tmp = "";
} else tmp += str[i];
}
// last word
r += reverseUtil(tmp);
return r;
}
console.log(reverse1("I like this program very much"));
你正在反转整个字符串。如果要使用单个函数并假设字符串仅包含 spaces,则可以遍历字符串的每个字符。
如果您遇到 space,您可以将其附加到结果中。如果您遇到另一个字符,您可以将其添加到一个临时字符串中以构建该单词的反向版本。
然后,当下一个字符是 space 或迭代中的最后一个字符时,将单词的反转版本附加到结果中。
function reverse1(str) {
let result = "", tmp = "";
for (let i = 0; i < str.length; i++) {
if (str[i] === ' ') {
result += ' '; continue;
}
tmp = str[i] + tmp;
if (str[i + 1] === undefined || str[i + 1] === ' ') {
result += tmp; tmp = "";
}
}
return result;
}
console.log(reverse1("I like this program very much"));
console.log(reverse1(" I like this program very much "));
console.log(reverse1("abc"));