从文件中读取行并在 Python 中的最后一个分隔符处拆分行并将其保存到另一个文件

Question

我有一个名为 data.txt 的文件，其中包含用冒号分隔的姓名、邮件和地址。它看起来像这样：

first_name1:last_name1:mail1@mail.com:address1
first_name2:last_name2:mail2@mail.com:address2
first_name3:last_name3:mail3@mail.com:address3
first_name4:last_name5:mail4@mail.com:address4
first_name5:last_name6:mail5@mail.com:address5
first_name6:last_name7:mail6@mail.com:address6
first_name7:last_name8:mail7@mail.com:address7

我只想读取地址并将其存储在名为 addresses.txt 的单独文件中（一行一个地址）。我试过这样的代码：

#name of file to store addresses
file_save = open("adresses.txt", 'a')

with open('data.txt', 'r') as file_to_open:
    data = file_to_open.read().rsplit(":",1)

    file_save.write(data[-1])

    print(data) #for testing only

file_to_open.close()

但它给了我这样的结果：

['first_name1:last_name1:mail1:address1\nfirst_name2:last_name2:mail2:address2\nfirst_name3:last_name3:mail3:address3\nfirst_name4:last_name5:mail4:address4\nfirst_name5:last_name6:mail5:address5\nfirst_name6:last_name7:mail6:address6\nfirst_name7:last_name8:mail7', 'address7']

我做错了什么？

我试着做成这样：

address1
address2
address3
...

请帮忙

Answer 1

使用csv和理解：

import csv 
with open('data.txt') as rf, open('address.txt', 'w') as wf:
    wf.writelines(a[-1] + '\n' for a in csv.reader(rf, delimiter=':'))

或没有csv:

with open('data.txt') as rf, open('address.txt', 'w') as wf:
    wf.writelines(a.split(':')[-1] for a in rf)

Answer 2

data = file_to_open.readlines()

for line in data:
    print(line.split(':')[-1])

Answer 3

file_save = open("adresses.txt", 'a')

with open('data.txt', 'r') as file_to_open:
    data = file_to_open.read().split("\n")  # first split into lines
    addresses = []  # initialize address list
    for line in data:
        address = line.split(":")[-1]  # get last element splitted by ":"
        addresses.append(address)  # save to addresses
    file_save.write("\n".join(addresses))  # one new line between each entry

file_save.close()  # this needs to be file_save not file_to_open

Answer 4

您可以尝试在 data

的每一行上使用 split 方法

file_save = open("adresses.txt", 'a')

with open('data.txt', 'r') as file_to_open:
    data = file_to_open.readlines();
    for address in data:
        file_save.write(address.split(":")[-1])

file_to_open.close()

Answer 5

我可以帮你。

我的 datas.txt 文件：

first_name1:last_name1:mail1@mail.com:address1
first_name2:last_name2:mail2@mail.com:address2
first_name3:last_name3:mail3@mail.com:address3
first_name4:last_name5:mail4@mail.com:address4
first_name5:last_name6:mail5@mail.com:address5
first_name6:last_name7:mail6@mail.com:address6
first_name7:last_name8:mail7@mail.com:address7

我的代码：

# My datas file
filename = 'datas.txt'

# A function for parse the lines
def get_lines():
    with open(filename, 'r', encoding='utf-8') as f:
        lines = f.readlines()
    return lines

def parse_and_extract():
    lines = get_lines()
    # First, we should open the result file.
    with open('result.txt', 'w', encoding='utf-8') as file:

        # Parse the lines and get the addresses
        for line in lines:
            # Get the address
            address = line.split(':')[-1]

            # Finally write the address to result file
            file.write(address)

parse_and_extract()

最后，我的 result.txt 文件：

address1
address2
address3
address4
address5
address6
address7

希望能帮到你

从文件中读取行并在 Python 中的最后一个分隔符处拆分行并将其保存到另一个文件

Read lines from file and split line on last delimiter in Python and save it to another file

python

string

split

delimiter