找到具有条件的对象数组的最小值

Question

    let event = [
    {
        "vendorBidId": 58,
        "participantName": "bro.gee@test.in",
        "bidAmount": 10000,
        "productionRate": 10000,
        "bidTime": "2021-10-21T14:55:05.957324",
        "isYou": false,
        "awarded": false
    },
    {
        "vendorBidId": 57,
        "participantName": "test@gmail.com",
        "bidAmount": 20000,
        "productionRate": 20000,
        "bidTime": "2021-10-21T14:50:24.493522",
        "isYou": false,
        "awarded": true
    },
    {
        "vendorBidId": null,
        "participantName": "bro+2@test.com",
        "bidAmount": 0,
        "productionRate": null,
        "bidTime": null,
        "isYou": false,
        "awarded": false
    },
    {
        "vendorBidId": null,
        "participantName": "bro.hey@test.com",
        "bidAmount": 0,
        "productionRate": null,
        "bidTime": null,
        "isYou": true,
        "awarded": false
    }
]

这里我想找到最低出价金额，但是在检查了以下条件后，

如果 vendorBidId 为空则跳过

我试过这样做。

let minimum = event.reduce(function(prev, curr) {
    return prev.bidAmount < curr.bidAmount ? prev : curr;
});

但是，我也尝试添加我的条件。但是效果不是很好

我只想要最低 bidAmount（如果 vendorBidId 为空则跳过）。

Answer 1

Math.min 在过滤器和地图上

let event = [{ "vendorBidId": 58, "participantName": "bro.gee@test.in", "bidAmount": 10000, "productionRate": 10000, "bidTime": "2021-10-21T14:55:05.957324", "isYou": false, "awarded": false }, { "vendorBidId": 57, "participantName": "test@gmail.com", "bidAmount": 20000, "productionRate": 20000, "bidTime": "2021-10-21T14:50:24.493522", "isYou": false, "awarded": true }, { "vendorBidId": null, "participantName": "bro+2@test.com", "bidAmount": 0, "productionRate": null, "bidTime": null, "isYou": false, "awarded": false }, { "vendorBidId": null, "participantName": "bro.hey@test.com", "bidAmount": 0, "productionRate": null, "bidTime": null, "isYou": true, "awarded": false } ]

const min = Math.min(...event
  .filter(evt => evt.vendorBidId)
  .map(({bidAmount}) => bidAmount)
);  

console.log(min)

Answer 2

使用 reduce 是一种简单的方法（如果您想要整个对象）。

如果您只需要最小值，可以在映射 minAmount 键值后使用 Math.min。

  let event = [
    {
        "vendorBidId": 58,
        "participantName": "bro.gee@test.in",
        "bidAmount": 10000,
        "productionRate": 10000,
        "bidTime": "2021-10-21T14:55:05.957324",
        "isYou": false,
        "awarded": false
    },
    {
        "vendorBidId": 57,
        "participantName": "test@gmail.com",
        "bidAmount": 20000,
        "productionRate": 20000,
        "bidTime": "2021-10-21T14:50:24.493522",
        "isYou": false,
        "awarded": true
    },
    {
        "vendorBidId": null,
        "participantName": "bro+2@test.com",
        "bidAmount": 0,
        "productionRate": null,
        "bidTime": null,
        "isYou": false,
        "awarded": false
    },
    {
        "vendorBidId": null,
        "participantName": "bro.hey@test.com",
        "bidAmount": 0,
        "productionRate": null,
        "bidTime": null,
        "isYou": true,
        "awarded": false
    }
]

const min = event.reduce(function(prev, curr) {
    return prev.bidAmount < curr.bidAmount && curr.vendorBidId ? prev : curr;
});

console.log(min);

var minValue = Math.min(...event.map(item => item.vendorBidId ?   item.bidAmount : 0));

console.log(minValue);

找到具有条件的对象数组的最小值

Find the minimum value of array of object with conditions

javascript

arrays

reduce

object