使用列表理解来获取 python 中具有多个 (3) 个元音的单词

Question

这是我的问题

fruits = ['mango', 'kiwi', 'strawberry', 'guava', 'pineapple', 'mandarin orange']

# Use a list comprehension to make a variable named fruits_with_more_than_two_vowels. Hint: You'll need a way to check if something is a vowel.

我可以单独在列表推导中完成吗？

Answer 1

您可以使用正则表达式模式来过滤掉辅音。

import re

fruits = ["mango", "kiwi", "strawberry", "guava", "pineapple", "mandarin orange"]
results = [i for i in fruits if len(re.sub(r"[^aeiouAEIOU]", "", i)) > 2]

以上代码产生以下输出。

>>> results
["guava", "pineapple", "mandarin orange"]

Answer 2

def vowels_check(word):
    vowels = 'aeiouAEIOU'
    count = 0
    for vowel in vowels:
        count += word.count(vowel)
    if count > 2: return True
    return False

fruits = ['mango', 'kiwi', 'strawberry', 'guava', 'pineapple', 'mandarin orange']
fruits_with_more_than_two_vowels = [fruit for fruit in fruits if vowels_check(fruit)]

使用列表理解来获取 python 中具有多个 (3) 个元音的单词

Using list comprehension to get the words with multiple (3) vowels in python

python

list-comprehension