(const_cast<char*>和without有什么区别？

Question

我很难理解这两个命令之间的区别

        char name[0x36];
        sprintf_s(name, "Some Text (%d%% Water) [%dm]", amount, dist);
        Drawing::RenderText(const_cast<char*>(name), screen, cfg.visuals.ships.textCol);

和

        char name[0x36];
        sprintf_s(name, "Some Text (%d%% Water) [%dm]", amount, dist);
        Drawing::RenderText(name, screen, cfg.visuals.ships.textCol);

这是 RenderText 函数：

void xD::Renderer::Drawing::RenderText(const char* text, const FVector2D& pos, const ImVec4& color, const bool outlined = true, const bool centered = true)
{
    if (!text) return;
    auto ImScreen = *reinterpret_cast<const ImVec2*>(&pos);
    if (centered)
    {
        auto size = ImGui::CalcTextSize(text);
        ImScreen.x -= size.x * 0.5f;
        ImScreen.y -= size.y;
    }
    auto window = ImGui::GetCurrentWindow();

    if (outlined) 
    { 
        window->DrawList->AddText(nullptr, 0.f, ImVec2(ImScreen.x - 1.f, ImScreen.y + 1.f), ImGui::GetColorU32(IM_COL32_BLACK), text); 
    }

    window->DrawList->AddText(nullptr, 0.f, ImScreen, ImGui::GetColorU32(color), text);

}

我正在使用 ImGui

Answer 1

What's the difference between (const_cast<char*> and without?

不同之处在于，在一种情况下转换是隐式的，而在另一种情况下转换是显式的。其他没有区别。

(const_cast<char*>和without有什么区别？

What's the difference between (const_cast<char*> and without?

c++

imgui