Laravel 包含重复数据的集合总和

Question

我有一个包含多个数据的对象，因为 controlNumber 每个 controlNumber 都有 shipment.qty 我想要的是将每个相同 controlNumber 的 qty 加起来=] 并显示一个 controlNumber 和总数量。

合集在下方

"collection": [
        {
            "id": 983,
            "controlNumber": 4498818,
            "ItemNumber": "PS2W12077",
            "shipment": {
                "id": 27,
                "Item": "PS2W12077",
                "ColorCode": "GRPFR",
                "qty": 1638
            }
        },
        {
            "id": 982,
            "controlNumber": 4498818,
            "ItemNumber": "PS2W12077",
            "shipment": {
                "id": 27,
                "Item": "PS2W12077",
                "ColorCode": "GRPFR",
                "qty": 1638
            }
        },
       {
            "id": 936,
            "controlNumber": 4498815,
            "ItemNumber": "PS2T01096",
            "shipment": {
                "id": 11,
                "Item": "PS2T01096",
                "ColorCode": "MALDI",
                "qty": 1212
            }
        },
 ]

controlNumber 4498818 有两个装运数据和两个 qty 我想要显示一个 controlNumber 总 qty 的 3276

我退休的是所有 controlNumber

中的 return 总数 qty

 $result = $collection->pipe(function ($collection) {
            return collect([
                'shipment_qty' => $collection->sum('shipment.qty'),

            ]);
        });

输出应该如下

"collection": [
        {
            "id": 983,
            "controlNumber": 4498818,
            "ItemNumber": "PS2W12077",
            "shipment": {
                "id": 27,
                "Item": "PS2W12077",
                "ColorCode": "GRPFR",
                "qty": 3276
            }
        },
       {
            "id": 936,
            "controlNumber": 4498815,
            "ItemNumber": "PS2T01096",
            "shipment": {
                "id": 11,
                "Item": "PS2T01096",
                "ColorCode": "MALDI",
                "qty": 1212
            }
        },
 ]

Answer 1

您可以使用 unique 收集方法根据控制编号值仅获取唯一项目：

 $uniqueCollection=$collection->unique('controlNumber');

 $result=$collection2->sum(function ($item){
           return $item->shipment->qty;
       });

Answer 2

这样你就得到了一个集合，其中键是 controlNumber，值是 shipment->qty.

的总和

$collection->mapToGroups(function ($item) {
   return [$item->controlNumber => $item->shipment->qty];
})->map->sum();

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