如何使用 gnu-efi 编译 uefi 应用程序?
How to compile uefi application using gnu-efi?
我尝试使用 gnu-efi
编译 uefi 代码。但是我不明白如何编译我的 uefi 应用程序代码。
我得到gnu-efi
3.0.2,解压并输入make && make install
。我写你好世界代码:
#include <efi.h>
#include <efilib.h>
EFI_STATUS efi_main (EFI_HANDLE ImageHandle, EFI_SYSTEM_TABLE *SystemTable) {
InitializeLib(ImageHandle, SystemTable);
Print(L"Hello, world!\n");
return EFI_SUCCESS;
}
我的 OS 是 Ubuntu 15.04.
包括 gnu-efi 文件
#include <efi.h>
#include <efilib.h>
看起来你的包含被 SO
删除了
创建 make 文件;
If you were building a "Hello, World" program for Linux in a Linux
environment, you could compile it without a Makefile. Building the
program in Linux for EFI, though, is essentially a cross-compilation
operation. As such, it necessitates using unusual compilation and
linker options, as well as a post-linking operation to convert the
program into a form that the EFI will accept. Although you could type
all the relevant commands by hand, a Makefile helps a lot.
ARCH = $(shell uname -m | sed s,i[3456789]86,ia32,)
OBJS = main.o
TARGET = hello.efi
EFIINC = /usr/include/efi
EFIINCS = -I$(EFIINC) -I$(EFIINC)/$(ARCH) -I$(EFIINC)/protocol
LIB = /usr/lib64
EFILIB = /usr/lib64/gnuefi
EFI_CRT_OBJS = $(EFILIB)/crt0-efi-$(ARCH).o
EFI_LDS = $(EFILIB)/elf_$(ARCH)_efi.lds
CFLAGS = $(EFIINCS) -fno-stack-protector -fpic \
-fshort-wchar -mno-red-zone -Wall
ifeq ($(ARCH),x86_64)
CFLAGS += -DEFI_FUNCTION_WRAPPER
endif
LDFLAGS = -nostdlib -znocombreloc -T $(EFI_LDS) -shared \
-Bsymbolic -L $(EFILIB) -L $(LIB) $(EFI_CRT_OBJS)
all: $(TARGET)
hello.so: $(OBJS)
ld $(LDFLAGS) $(OBJS) -o $@ -lefi -lgnuefi
%.efi: %.so
objcopy -j .text -j .sdata -j .data -j .dynamic \
-j .dynsym -j .rel -j .rela -j .reloc \
--target=efi-app-$(ARCH) $^ $@
参考:
在 Ubuntu 18.04 中,这两行:
LIB = /usr/lib64
EFILIB = /usr/lib64/gnuefi
需要改为:
LIB = /usr/lib
EFILIB = /usr/lib
我尝试使用 gnu-efi
编译 uefi 代码。但是我不明白如何编译我的 uefi 应用程序代码。
我得到gnu-efi
3.0.2,解压并输入make && make install
。我写你好世界代码:
#include <efi.h>
#include <efilib.h>
EFI_STATUS efi_main (EFI_HANDLE ImageHandle, EFI_SYSTEM_TABLE *SystemTable) {
InitializeLib(ImageHandle, SystemTable);
Print(L"Hello, world!\n");
return EFI_SUCCESS;
}
我的 OS 是 Ubuntu 15.04.
包括 gnu-efi 文件
#include <efi.h> #include <efilib.h>
看起来你的包含被 SO
删除了
创建 make 文件;
If you were building a "Hello, World" program for Linux in a Linux environment, you could compile it without a Makefile. Building the program in Linux for EFI, though, is essentially a cross-compilation operation. As such, it necessitates using unusual compilation and linker options, as well as a post-linking operation to convert the program into a form that the EFI will accept. Although you could type all the relevant commands by hand, a Makefile helps a lot.
ARCH = $(shell uname -m | sed s,i[3456789]86,ia32,)
OBJS = main.o
TARGET = hello.efi
EFIINC = /usr/include/efi
EFIINCS = -I$(EFIINC) -I$(EFIINC)/$(ARCH) -I$(EFIINC)/protocol
LIB = /usr/lib64
EFILIB = /usr/lib64/gnuefi
EFI_CRT_OBJS = $(EFILIB)/crt0-efi-$(ARCH).o
EFI_LDS = $(EFILIB)/elf_$(ARCH)_efi.lds
CFLAGS = $(EFIINCS) -fno-stack-protector -fpic \
-fshort-wchar -mno-red-zone -Wall
ifeq ($(ARCH),x86_64)
CFLAGS += -DEFI_FUNCTION_WRAPPER
endif
LDFLAGS = -nostdlib -znocombreloc -T $(EFI_LDS) -shared \
-Bsymbolic -L $(EFILIB) -L $(LIB) $(EFI_CRT_OBJS)
all: $(TARGET)
hello.so: $(OBJS)
ld $(LDFLAGS) $(OBJS) -o $@ -lefi -lgnuefi
%.efi: %.so
objcopy -j .text -j .sdata -j .data -j .dynamic \
-j .dynsym -j .rel -j .rela -j .reloc \
--target=efi-app-$(ARCH) $^ $@
参考:
在 Ubuntu 18.04 中,这两行:
LIB = /usr/lib64
EFILIB = /usr/lib64/gnuefi
需要改为:
LIB = /usr/lib
EFILIB = /usr/lib