我如何 return 来自 php 的特定数组数据？

Question

我正在使用 async/await 获取一个文件 (createCharge.php)，当在 checkout.html

上单击 <button> 时，该文件包含包含内部数据的数组

如果我使用 print_r 我可以在控制台中看到所有结果，例如名称、描述、数量，甚至是新生成的 'hosted_url' 客户将使用它来继续付款。

问题是我不知道如何将 hosted_url 结果提取到结帐页面和 <a href="">Pay now!</a>。

这就是我的 checkout.html...

<button id="btn">Pay with Crypto?</button>

<p id="pay"></p>

<script>
  btn.addEventListener('click', async (e) => {e.preventDefault();
  const response = await fetch('coinbasePHPtest/createCharge.php/');
  if (!response.ok) {
  const errorMessage = await response.text();
  console.error(response.status, response.statusText, errorMessage);
  alert('There was an error creating the charge.');
  return;
  }            
  const newurl = await response.text();
  console.log(newurl);
      
  pay.innerHTML = `<a href="${newurl}">Pay Now! - Coinbase</a>`;
  });
</script>

你可以看到我正在尝试将 hosted_url 放入 <script> 内的 <a> 标签中。

这是我的 createCharge.php，它实际上创建了 hosted_url...（示例：https://commerce.coinbase.com/charges/xxxxx）

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL, 'https://api.commerce.coinbase.com/charges');
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode(
array (
'name' => 'My-Company',
'description' => 'Selected Product',
'local_price' => 
array (
'amount' => '147.00',
'currency' => 'GBP',
),
'pricing_type' => 'fixed_price',
'metadata' => 
array (
'customer_id' => 'id_1',
'customer_name' => 'Satoshi Nakamoto',
),
'redirect_url' => 'https://www.my-site.co.uk/Checkout/payment_successful.php',
'cancel_url' => 'https://www.my-site.co.uk/Checkout/payment_cancelled.php',
)
));

$headers = array();
$headers[] = 'Content-Type: application/json';
$headers[] = 'X-Cc-Api-Key: MY-API-KEY';
$headers[] = 'X-Cc-Version: 2018-03-22';
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);

$result = curl_exec($ch);

curl_close($ch);


$response = json_decode($result, true);

return $response->data->hosted_url;

?>

我也试过了..

pay.innerHTML = `<a href="${hosted_url}">Pay Now!</a>`

pay.innerHTML = `<a href="{hosted_url}">Pay Now!</a>`

pay.innerHTML = `<a href="${newurl->hosted_url}">Pay Now!</a>`

pay.innerHTML = `<a href="{.hosted_url}">Pay Now!</a>`

运气不好。

和...

btn.onclick = async() => {
const response = await fetch('coinbasePHPtest/charge.php/hosted_url');
const data = await response.json();

&

btn.onclick = async() => {
const resp = await fetch(`coinbasePHPtest/createCharge.php/${hosted_url}`);
const data = await resp.json();

解法：

$result = curl_exec($ch);

curl_close($ch);

$response = json_decode($result, true);

echo $response['data']['hosted_url'];

createCharge.php 中的这段代码对我有用！ :)

Answer 1

我想你只想输出数据而不是使用 return。替换

return $response->data->hosted_url;

和

echo $response['data']['hosted_url'];

我如何 return 来自 php 的特定数组数据？

How do I return specific array data from php?

php

arrays

curl

async-await

coinbase-api