将txt文件中的int值转换为float

Question

我有这样的 txt 文件 f1= 255,216,255,224,0,16,74,70,73,70,0,1,1,1,0,0,0,0,0,0,255,219,0 我需要将这些数字转换为浮点数并保存在 f2 中（f2 包含转换后的浮点值）该怎么做？

Answer 1

假设输入正确，使用列表理解：

with open(file_path, "r") as f_r:
    num_strs = f_r.read().split(",")
    num_floats = [float(x) for x in num_strs]

如果您想将输出写入文件：

separator = ","
with open(file_path, "w") as f_w:
    f_w.write(separator.join([str(x) for x in num_floats]))

这会将浮点数的默认字符串表示形式写入文件如果您还想格式化浮点数（例如设置精度）：

separator = ","
with open(file_path, "w") as f_w:
    f_w.write(separator.join([f"{x:.2f}" for x in num_floats]))

Answer 2

我写了一行:D

import pathlib

# Read the text file, split it by commas, then convert all items to floats
output = list(map(float, pathlib.Path("file.txt").read_text().split(",")))

Answer 3

import numpy as np
numbers = np.loadtxt("file.txt",  delimiter=",")
#It should parse it as float64 already, but just in case:
numbers=np.float64(numbers)
with open("file2.txt", "w") as txt_file:
    for number in numbers:
        txt_file.write("".join(str(number)) + ",")

将txt文件中的int值转换为float

Convert int value in txt file to float

python

python-3.x

txt