我如何在c中解析这个文件

Question

如何从词义中拆分单词 1. 猛犸象：大

我的代码：

void ReadFromFile(){
FILE *dictionary = fopen("dictionary.txt", "r");
char word[20];
char meaning[50];
while(fscanf(dictionary, "%[^:]:%[^\t]\t", word, meaning) == 2){
    printf("%s %s\n", word, meaning);
}
fclose(dictionary);

Answer 1

假设 word 和 meaning 不包含数字和点，我的方法如下：

首先，将数字和点上的输入行拆分为标记形式为 word: meaning.
接下来用冒号分隔每个标记。
最后，删除开头和结尾的空白字符。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define INFILE "dictionary.txt"

void split(char *str);
void separate(char *str);
char *trim(char *str);

/*
 * split line on serial number into "word" and "meaning" pairs
 * WARNING: the array of "str" is modified
 */
void
split(char *str)
{
    char *tk;                           // pointer to each token
    char delim[] = "0123456789.";       // characters used in the serial number

    tk = strtok(str, delim);            // get the first token
    while (tk != NULL) {
        separate(tk);                   // separate each token
        tk = strtok(NULL, delim);       // get the next token
    }
}

/*
 * separate the pair into "word" and "meaning" and print them
 */
void
separate(char *str)
{
    char *p;
    if (NULL == (p = index(str, ':'))) {
                                        // search a colon character in "str"
        fprintf(stderr, "Illegal format: %s\n", str);
        exit(1);
    }
    *p++ = '[=10=]';                        // terminate the "word" string
                                        // now "p" points to the start of "meaning"
    printf("%s %s\n", trim(str), trim(p));
}

/*
 * remove leading and trailing whitespaces
 * WARNING: the array of "str" is modified
 */
char *
trim(char *str)
{
    char *p;
    for (p = str; *p != '[=10=]'; p++);     // jump to the end of "str"
    for (; p > str && (*p == ' ' || *p == '\t' || *p == '\r' || *p == '\n' || *p == '[=10=]'); p--);
                                        // rewind the pointer skipping blanks
    *++p = '[=10=]';                        // chop the trailing blanks off
    for (p = str; *p != '[=10=]' && (*p == ' ' || *p == '\t' || *p == '\r' || *p == '\n'); p++);
                                        // skip leading blanks
    return p;
}

int
main()
{
    FILE *fp;
    char str[BUFSIZ];

    if (NULL == (fp = fopen(INFILE, "r"))) {
        perror(INFILE);
        exit(1);
    }

    while (NULL != fgets(str, BUFSIZ, fp)) {
        split(trim(str));
    }

    fclose(fp);
    return 0;
}

输出：

foe enemy
vast huge
purchase buy
drowsy sleepy
absent missing
prank trick
[snip]

[备选]
我想 C 可能不是适合这种字符串操作的语言。 python、perl 或 ruby 等高级语言将用更少的代码解决它。这是一个 python 的例子，它会产生相同的结果：

import re

with open("dictionary.txt") as f:
    s = f.read()

for m in re.finditer(r'\d+\.\s*(.+?):\s*(\S+)', s):
    print(m.group(1) + " " + m.group(2))

我如何在c中解析这个文件

how can i parse this file in c

c

parsing

split

file-handling