停止使用 DB::DB 创建的分析器以在未真正调用的情况下第二次显示调用
Stopping a profiler created with DB::DB to show a call a second time where it wasn't really called
在寻找在我使用的框架中记录所有使用过的子例程的可能性时,我发现了这个 。最佳答案使用子例程 DB::DB 来记录所有使用的子例程。
这在一定程度上起作用,与 caller() 一起使用,以找出程序采用的路径。
但是我有一个问题,当程序 returns 从一个函数进入一个新的函数时,子程序被第二次“调用”。
我的 DB::DB 在 /etc/perl/Devel/AllSubs.pm
package Devel::AllSubs;
use Data::Dumper;
$Data::Dumper::Sortkeys = 1;
my $LastSub = '::';
sub DB::DB {
my ($Package, $Filename, $Line, $Subroutine) = caller(1);
if ($Subroutine ne $LastSub ){
print STDERR Data::Dumper->Dump(
[
$Package,
$Filename,
$Line,
$Subroutine
],
['Package-1', 'Filename-1', 'Line-1', "Subroutine-1"]
);
COUNT:
for ( my $Count = 2; $Count < 30; $Count++ ) {
my ( $NextPackage, $NextFilename, $NextLine, $NextSubroutine ) = caller( $Count );
last COUNT if !$NextLine;
print STDERR Data::Dumper->Dump(
[
$NextPackage,
$NextFilename,
$NextLine,
$NextSubroutine
],
["Package-$Count", "Filename-$Count", "Line-$Count", "Subroutine-$Count",]
);
}
say STDERR "";
$LastSub = $Subroutine;
}
}
1;
我想检查其调用的程序perl -d:AllSubs AllTest.pl
&One();
sub One {
&Two();
}
sub Two {
&Three();
&Six();
}
sub Three {
&Four();
&Five();
}
sub Four {}
sub Five {}
sub Six {}
1;
上面提到的答案声称,每个子程序都会调用 DB::DB,所以我的预期结果是:
# One
# Two
# Three
# Four
# Five
# Six
我得到的是:
# One
# Two
# Three
# Four
# Three
# Five
# Two
# Six
完整的转储程序输出是:
$Package-1 = undef;
$Filename-1 = undef;
$Line-1 = undef;
$Subroutine-1 = undef;
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 30;
$Subroutine-1 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 34;
$Subroutine-1 = 'main::Two';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 30;
$Subroutine-2 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 38;
$Subroutine-1 = 'main::Three';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 34;
$Subroutine-2 = 'main::Two';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 30;
$Subroutine-3 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 43;
$Subroutine-1 = 'main::Four';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 38;
$Subroutine-2 = 'main::Three';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 34;
$Subroutine-3 = 'main::Two';
$Package-4 = 'main';
$Filename-4 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-4 = 30;
$Subroutine-4 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 38;
$Subroutine-1 = 'main::Three';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 34;
$Subroutine-2 = 'main::Two';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 30;
$Subroutine-3 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 44;
$Subroutine-1 = 'main::Five';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 38;
$Subroutine-2 = 'main::Three';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 34;
$Subroutine-3 = 'main::Two';
$Package-4 = 'main';
$Filename-4 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-4 = 30;
$Subroutine-4 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 34;
$Subroutine-1 = 'main::Two';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 30;
$Subroutine-2 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 39;
$Subroutine-1 = 'main::Six';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 34;
$Subroutine-2 = 'main::Two';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 30;
$Subroutine-3 = 'main::One';
$Package-1 = undef;
$Filename-1 = undef;
$Line-1 = undef;
$Subroutine-1 = undef;
有什么方法可以跳过 DB::DB 被调用的情况,即使它没有在代码中被调用第二次?
编辑:
我取得了一些进步。 DB::DB 为每一行代码调用。 DB::sub 另一方面是我需要的。如果我在这里使用 caller(),我会得到 caller(0) 的前一个 sub。当前子在 $DB::sub
。但我还需要文件名和调用此 sub 的行。它说 here that $DB::filename
should contain the filename, but it is empty. I also found some information in this perl4 book,但目前还不足以帮助我。
这是一个似乎可行的示例:
lib/Devel/MyDebugger.pm:
package Devel::MyDebugger;
package DB;
use feature qw(say);
use warnings;
our $sub;
our $dbline;
our $dbpack;
our $dbfile;
our $START_DEBUG = 0;
sub DB {
($dbpack, $dbfile, $dbline) = caller;
}
sub sub {
if ("$sub" eq "main::One") {
$START_DEBUG = 1;
}
if ($START_DEBUG) {
say "";
say "[sub = $sub, lineno = $dbline, pack = $dbpack, file = $dbfile]";
for ( my $frame = 0; $frame < 30; $frame++ ) {
my @info = my ($package, $filename, $line, $subroutine) = caller $frame;
last if !$line;
print_info($frame, @info);
}
}
&$sub;
}
sub print_info {
my ($frame, $package, $filename, $line, $subroutine) = @_;
my $indent = " " x $frame;
say "${indent}Package-$frame: $package";
say "${indent}Filename-$frame: $filename";
say "${indent}Line-$frame: $line";
say "${indent}Subroutine-$frame: $subroutine";
}
p.pl:
#! /usr/bin/env perl
use strict;
use warnings;
&One();
sub One {
&Two();
}
sub Two {
&Three();
&Six();
}
sub Three {
&Four();
&Five();
}
sub Four { }
sub Five { }
sub Six { }
运行 调试器是这样的:
$ perl -I./lib -d:MyDebugger p.pl
输出:
[sub = main::One, lineno = 6, pack = main, file = p.pl]
[sub = main::Two, lineno = 8, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 6
Subroutine-0: main::One
[sub = main::Three, lineno = 11, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 8
Subroutine-0: main::Two
Package-1: main
Filename-1: p.pl
Line-1: 6
Subroutine-1: main::One
[sub = main::Four, lineno = 15, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 11
Subroutine-0: main::Three
Package-1: main
Filename-1: p.pl
Line-1: 8
Subroutine-1: main::Two
Package-2: main
Filename-2: p.pl
Line-2: 6
Subroutine-2: main::One
[sub = main::Five, lineno = 16, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 11
Subroutine-0: main::Three
Package-1: main
Filename-1: p.pl
Line-1: 8
Subroutine-1: main::Two
Package-2: main
Filename-2: p.pl
Line-2: 6
Subroutine-2: main::One
[sub = main::Six, lineno = 12, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 8
Subroutine-0: main::Two
Package-1: main
Filename-1: p.pl
Line-1: 6
Subroutine-1: main::One
在寻找在我使用的框架中记录所有使用过的子例程的可能性时,我发现了这个
我的 DB::DB 在 /etc/perl/Devel/AllSubs.pm
package Devel::AllSubs;
use Data::Dumper;
$Data::Dumper::Sortkeys = 1;
my $LastSub = '::';
sub DB::DB {
my ($Package, $Filename, $Line, $Subroutine) = caller(1);
if ($Subroutine ne $LastSub ){
print STDERR Data::Dumper->Dump(
[
$Package,
$Filename,
$Line,
$Subroutine
],
['Package-1', 'Filename-1', 'Line-1', "Subroutine-1"]
);
COUNT:
for ( my $Count = 2; $Count < 30; $Count++ ) {
my ( $NextPackage, $NextFilename, $NextLine, $NextSubroutine ) = caller( $Count );
last COUNT if !$NextLine;
print STDERR Data::Dumper->Dump(
[
$NextPackage,
$NextFilename,
$NextLine,
$NextSubroutine
],
["Package-$Count", "Filename-$Count", "Line-$Count", "Subroutine-$Count",]
);
}
say STDERR "";
$LastSub = $Subroutine;
}
}
1;
我想检查其调用的程序perl -d:AllSubs AllTest.pl
&One();
sub One {
&Two();
}
sub Two {
&Three();
&Six();
}
sub Three {
&Four();
&Five();
}
sub Four {}
sub Five {}
sub Six {}
1;
上面提到的答案声称,每个子程序都会调用 DB::DB,所以我的预期结果是:
# One
# Two
# Three
# Four
# Five
# Six
我得到的是:
# One
# Two
# Three
# Four
# Three
# Five
# Two
# Six
完整的转储程序输出是:
$Package-1 = undef;
$Filename-1 = undef;
$Line-1 = undef;
$Subroutine-1 = undef;
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 30;
$Subroutine-1 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 34;
$Subroutine-1 = 'main::Two';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 30;
$Subroutine-2 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 38;
$Subroutine-1 = 'main::Three';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 34;
$Subroutine-2 = 'main::Two';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 30;
$Subroutine-3 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 43;
$Subroutine-1 = 'main::Four';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 38;
$Subroutine-2 = 'main::Three';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 34;
$Subroutine-3 = 'main::Two';
$Package-4 = 'main';
$Filename-4 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-4 = 30;
$Subroutine-4 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 38;
$Subroutine-1 = 'main::Three';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 34;
$Subroutine-2 = 'main::Two';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 30;
$Subroutine-3 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 44;
$Subroutine-1 = 'main::Five';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 38;
$Subroutine-2 = 'main::Three';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 34;
$Subroutine-3 = 'main::Two';
$Package-4 = 'main';
$Filename-4 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-4 = 30;
$Subroutine-4 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 34;
$Subroutine-1 = 'main::Two';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 30;
$Subroutine-2 = 'main::One';
$Package-1 = 'main';
$Filename-1 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-1 = 39;
$Subroutine-1 = 'main::Six';
$Package-2 = 'main';
$Filename-2 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-2 = 34;
$Subroutine-2 = 'main::Two';
$Package-3 = 'main';
$Filename-3 = '/opt/frameworks/test/scripts/AllTest.pl';
$Line-3 = 30;
$Subroutine-3 = 'main::One';
$Package-1 = undef;
$Filename-1 = undef;
$Line-1 = undef;
$Subroutine-1 = undef;
有什么方法可以跳过 DB::DB 被调用的情况,即使它没有在代码中被调用第二次?
编辑:
我取得了一些进步。 DB::DB 为每一行代码调用。 DB::sub 另一方面是我需要的。如果我在这里使用 caller(),我会得到 caller(0) 的前一个 sub。当前子在 $DB::sub
。但我还需要文件名和调用此 sub 的行。它说 here that $DB::filename
should contain the filename, but it is empty. I also found some information in this perl4 book,但目前还不足以帮助我。
这是一个似乎可行的示例:
lib/Devel/MyDebugger.pm:
package Devel::MyDebugger;
package DB;
use feature qw(say);
use warnings;
our $sub;
our $dbline;
our $dbpack;
our $dbfile;
our $START_DEBUG = 0;
sub DB {
($dbpack, $dbfile, $dbline) = caller;
}
sub sub {
if ("$sub" eq "main::One") {
$START_DEBUG = 1;
}
if ($START_DEBUG) {
say "";
say "[sub = $sub, lineno = $dbline, pack = $dbpack, file = $dbfile]";
for ( my $frame = 0; $frame < 30; $frame++ ) {
my @info = my ($package, $filename, $line, $subroutine) = caller $frame;
last if !$line;
print_info($frame, @info);
}
}
&$sub;
}
sub print_info {
my ($frame, $package, $filename, $line, $subroutine) = @_;
my $indent = " " x $frame;
say "${indent}Package-$frame: $package";
say "${indent}Filename-$frame: $filename";
say "${indent}Line-$frame: $line";
say "${indent}Subroutine-$frame: $subroutine";
}
p.pl:
#! /usr/bin/env perl
use strict;
use warnings;
&One();
sub One {
&Two();
}
sub Two {
&Three();
&Six();
}
sub Three {
&Four();
&Five();
}
sub Four { }
sub Five { }
sub Six { }
运行 调试器是这样的:
$ perl -I./lib -d:MyDebugger p.pl
输出:
[sub = main::One, lineno = 6, pack = main, file = p.pl]
[sub = main::Two, lineno = 8, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 6
Subroutine-0: main::One
[sub = main::Three, lineno = 11, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 8
Subroutine-0: main::Two
Package-1: main
Filename-1: p.pl
Line-1: 6
Subroutine-1: main::One
[sub = main::Four, lineno = 15, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 11
Subroutine-0: main::Three
Package-1: main
Filename-1: p.pl
Line-1: 8
Subroutine-1: main::Two
Package-2: main
Filename-2: p.pl
Line-2: 6
Subroutine-2: main::One
[sub = main::Five, lineno = 16, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 11
Subroutine-0: main::Three
Package-1: main
Filename-1: p.pl
Line-1: 8
Subroutine-1: main::Two
Package-2: main
Filename-2: p.pl
Line-2: 6
Subroutine-2: main::One
[sub = main::Six, lineno = 12, pack = main, file = p.pl]
Package-0: main
Filename-0: p.pl
Line-0: 8
Subroutine-0: main::Two
Package-1: main
Filename-1: p.pl
Line-1: 6
Subroutine-1: main::One