如何在 JSP 中找到 LDAP 用户的 DN?
How can I find an LDAP user's DN in JSP?
我正在尝试在 JSP 的 LDAP 树中查找用户的 OU。我可以使用以下代码检索许多用户的 LDAP 属性:
Hashtable<String, String> tenv = new Hashtable<String, String>();
tenv.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
tenv.put(Context.PROVIDER_URL, "ldap://xx.xx.xx.xx:389/");
SearchControls sc = new SearchControls();
sc.setSearchScope(SearchControls.SUBTREE_SCOPE);
LdapContext lctx = new InitialLdapContext(tenv, null);
String filter = "cn=" + userid;
NamingEnumeration res = lctx.search ("dc=my,dc=dom,dc=org", filter, sc);
while (res.hasMore())
{
SearchResult s = (SearchResult) res.next();
Attributes attrs = s.getAttributes();
Attribute attr = attrs.get("SN");
out.println ("<font color=red>" + attr + "</font>");
}
当我在 Linux 命令行 运行 ldapsearch 时,使用类似的搜索参数,我可以看到一个 DN: 显示用户所在的 OU (dn: uid=用户名,ou=用户,dc=my,dc=dom,dc=org)。
我试过 attrs.get("DN") 并返回 null。如何检索此 DN:在 JSP?
显然有“there is no direct way of obtaining the Distinguished Name (DN) from the search results.”
这段代码可以做到:
import java.util.Hashtable;
import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.Attribute;
import javax.naming.directory.Attributes;
import javax.naming.directory.DirContext;
import javax.naming.directory.InitialDirContext;
import javax.naming.ldap.*;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
class GetAllAttrs
{
public static void main(String[] args)
{
String filter = "cn=myuser"; // this is the user to look for
String baseDN = "dc=my,dc=dom,dc=org";
String ldapURL = "ldap://192.168.101.1:389";
// Set up the environment for creating the initial context
Hashtable<String, Object> env = new Hashtable<String, Object>(11);
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, ldapURL);
try
{
// Create the initial context
LdapContext ctx = new InitialLdapContext(env, null);
SearchControls sc = new SearchControls();
sc.setSearchScope(SearchControls.SUBTREE_SCOPE);
NamingEnumeration res = ctx.search (baseDN, filter, sc);
while (res.hasMore())
{
SearchResult s = (SearchResult) res.next();
// print user's DN
System.out.println(">>" + s.getNameInNamespace());
}
// Close the context when we're done
ctx.close();
}
catch (Exception e)
{
e.printStackTrace();
}
}
}
我正在尝试在 JSP 的 LDAP 树中查找用户的 OU。我可以使用以下代码检索许多用户的 LDAP 属性:
Hashtable<String, String> tenv = new Hashtable<String, String>();
tenv.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
tenv.put(Context.PROVIDER_URL, "ldap://xx.xx.xx.xx:389/");
SearchControls sc = new SearchControls();
sc.setSearchScope(SearchControls.SUBTREE_SCOPE);
LdapContext lctx = new InitialLdapContext(tenv, null);
String filter = "cn=" + userid;
NamingEnumeration res = lctx.search ("dc=my,dc=dom,dc=org", filter, sc);
while (res.hasMore())
{
SearchResult s = (SearchResult) res.next();
Attributes attrs = s.getAttributes();
Attribute attr = attrs.get("SN");
out.println ("<font color=red>" + attr + "</font>");
}
当我在 Linux 命令行 运行 ldapsearch 时,使用类似的搜索参数,我可以看到一个 DN: 显示用户所在的 OU (dn: uid=用户名,ou=用户,dc=my,dc=dom,dc=org)。 我试过 attrs.get("DN") 并返回 null。如何检索此 DN:在 JSP?
显然有“there is no direct way of obtaining the Distinguished Name (DN) from the search results.”
这段代码可以做到:
import java.util.Hashtable;
import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.Attribute;
import javax.naming.directory.Attributes;
import javax.naming.directory.DirContext;
import javax.naming.directory.InitialDirContext;
import javax.naming.ldap.*;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
class GetAllAttrs
{
public static void main(String[] args)
{
String filter = "cn=myuser"; // this is the user to look for
String baseDN = "dc=my,dc=dom,dc=org";
String ldapURL = "ldap://192.168.101.1:389";
// Set up the environment for creating the initial context
Hashtable<String, Object> env = new Hashtable<String, Object>(11);
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.PROVIDER_URL, ldapURL);
try
{
// Create the initial context
LdapContext ctx = new InitialLdapContext(env, null);
SearchControls sc = new SearchControls();
sc.setSearchScope(SearchControls.SUBTREE_SCOPE);
NamingEnumeration res = ctx.search (baseDN, filter, sc);
while (res.hasMore())
{
SearchResult s = (SearchResult) res.next();
// print user's DN
System.out.println(">>" + s.getNameInNamespace());
}
// Close the context when we're done
ctx.close();
}
catch (Exception e)
{
e.printStackTrace();
}
}
}