SQL Presto:不支持相关子查询
SQL Presto: correlated subquery is not supported
考虑 table x
id,val
1,100
3,300
和tabley
id
1
2
3
对于 y
的每一行,我想要来自 x
的 val
,其中来自 y 的 id
等于或最接近 id
来自 x
这样的:
id,val
1,100
2,100
3,300
我试图找到与相关子查询最接近的 ID:
WITH
x AS (SELECT * FROM (VALUES (1, 100),(3, 300)) AS t(id, val)),
y AS (SELECT * FROM (VALUES 1,2,3) AS t(id))
SELECT *, (
SELECT x.id
FROM x
WHERE x.id <= y.id
ORDER BY x.id DESC
LIMIT 1
) as closest_id
FROM y
但是我明白了
SYNTAX_ERROR: line 5:5: Given correlated subquery is not supported
我也试过左连接:
SELECT *
FROM y
LEFT JOIN x ON x.id <= (
SELECT MAX(xbis.id) FROM x AS xbis WHERE xbis.id <= y.id
)
但是我得到了错误
SYNTAX_ERROR: line 7:5: Correlated subquery in given context is not supported
你这样使用我认为它的工作...
SELECT *, (
SELECT top 1 x.val
FROM x
WHERE x.id <= y.id
ORDER BY x.id DESC
) as closest_id
FROM y
您可以尝试根据less then条件加入,然后对结果进行分组,从分组中找到需要的数据:
WITH
x AS (SELECT * FROM (VALUES (1, 100),(3, 300),(4, 400)) AS t(id, val)),
y AS (SELECT * FROM (VALUES 1,2,3,4) AS t(id))
SELECT y.id as yId,
max(x.id) as xId,
max_by(x.val, x.id) as val
FROM y
JOIN x on x.id <= y.id
GROUP BY y.id
ORDER BY y.id
输出:
yId
xId
val
1
1
100
2
1
100
3
3
300
4
4
400
考虑 table x
id,val
1,100
3,300
和tabley
id
1
2
3
对于 y
的每一行,我想要来自 x
的 val
,其中来自 y 的 id
等于或最接近 id
来自 x
这样的:
id,val
1,100
2,100
3,300
我试图找到与相关子查询最接近的 ID:
WITH
x AS (SELECT * FROM (VALUES (1, 100),(3, 300)) AS t(id, val)),
y AS (SELECT * FROM (VALUES 1,2,3) AS t(id))
SELECT *, (
SELECT x.id
FROM x
WHERE x.id <= y.id
ORDER BY x.id DESC
LIMIT 1
) as closest_id
FROM y
但是我明白了
SYNTAX_ERROR: line 5:5: Given correlated subquery is not supported
我也试过左连接:
SELECT *
FROM y
LEFT JOIN x ON x.id <= (
SELECT MAX(xbis.id) FROM x AS xbis WHERE xbis.id <= y.id
)
但是我得到了错误
SYNTAX_ERROR: line 7:5: Correlated subquery in given context is not supported
你这样使用我认为它的工作...
SELECT *, (
SELECT top 1 x.val
FROM x
WHERE x.id <= y.id
ORDER BY x.id DESC
) as closest_id
FROM y
您可以尝试根据less then条件加入,然后对结果进行分组,从分组中找到需要的数据:
WITH
x AS (SELECT * FROM (VALUES (1, 100),(3, 300),(4, 400)) AS t(id, val)),
y AS (SELECT * FROM (VALUES 1,2,3,4) AS t(id))
SELECT y.id as yId,
max(x.id) as xId,
max_by(x.val, x.id) as val
FROM y
JOIN x on x.id <= y.id
GROUP BY y.id
ORDER BY y.id
输出:
yId | xId | val |
---|---|---|
1 | 1 | 100 |
2 | 1 | 100 |
3 | 3 | 300 |
4 | 4 | 400 |