Firebase pubsub 功能在模拟器中有效，但在生产中不能立即 returns

Question

我预定的功能



// TODO;
export const reportUsage =
  fun.pubsub.schedule("0 0 1 * *").onRun(async (context) => {
    functions.logger.debug("Initialising db");
    const db = admin.firestore();
    const users = await db.collection("users").get();
    users.docs.forEach( async (doc) => {
      functions.logger.debug("Got list of users. Looping..");
      const userData = doc.data();
      const SOME_DATA:number = userData["SOME_DATA"];
      functions.logger.debug("got SOME_DATA of this user");
      const SOME_DATAIntPart:number =
       parseInt(SOME_DATA.toFixed(20).split(".")[0]);
      const SOME_DATAFloatPart:number =
       parseFloat("0." + SOME_DATA.toFixed(20).split(".")[1]);
      const subItemId =
       userData["stripeInfo"]["subscription"]["items"]["data"][0]["id"];
      functions.logger.debug("got sub id of this user");
      await stripe.subscriptionItems.createUsageRecord(subItemId, {
        quantity: SOME_DATAIntPart,
        timestamp: admin.firestore.Timestamp.now().seconds,
      }, {
        timeout: 60,
        maxNetworkRetries: 5,
      });
      functions.logger.debug("got reported to stripe");
      await doc.ref.update({
        "SOME_DATA": SOME_DATAFloatPart,
      });
      functions.logger.debug("updated SOME_DATA");
      return null;
    });
  });

当我从 Cloud Scheduler 手动运行函数时，它 returns 就在 Stripe 调用之前

 await stripe.subscriptionItems.createUsageRecord(subItemId, {
        quantity: SOME_DATAIntPart,
        timestamp: admin.firestore.Timestamp.now().seconds,
      }, {
        timeout: 60,
        maxNetworkRetries: 5,
      });

我记录的日志显示了这个

如您所见，它在执行 Stripe 调用之前立即 returns。

上次日志中的错误是这样的：

但是，运行使用函数 shell 调用函数、firestore 和 pubsub 模拟器，我可以调用 reportUsage 函数，这就是打印出来的内容

谁能告诉我为什么 pubsub 功能在生产环境中不起作用？

Answer 1

您不应在 forEach() 循环中使用 async/await，请参阅 "JavaScript: async/await with forEach()" and 。

您可以按如下方式使用Promise.all()：

export const reportUsage = fun.pubsub
  .schedule('0 0 1 * *')
  .onRun(async (context) => {
    functions.logger.debug('Initialising db');

    const db = admin.firestore();
    const users = await db.collection('users').get();

    users.docs.forEach((doc) => {
      functions.logger.debug('Got list of users. Looping..');
      const userData = doc.data();
      const SOME_DATA: number = userData['SOME_DATA'];
      functions.logger.debug('got SOME_DATA of this user');
      const SOME_DATAIntPart: number = parseInt(
        SOME_DATA.toFixed(20).split('.')[0]
      );
      const SOME_DATAFloatPart: number = parseFloat(
        '0.' + SOME_DATA.toFixed(20).split('.')[1]
      );
      const subItemId =
        userData['stripeInfo']['subscription']['items']['data'][0]['id'];
      functions.logger.debug('got sub id of this user');

      const promises = [];
      // We push a Promise to the promsies Array. Note that the then() method returns a promise.
      promises.push(
        stripe.subscriptionItems
          .createUsageRecord(
            subItemId,
            {
              quantity: SOME_DATAIntPart,
              timestamp: admin.firestore.Timestamp.now().seconds,
            },
            {
              timeout: 60,
              maxNetworkRetries: 5,
            }
          )
          .then(() => {
            return doc.ref.update({
              SOME_DATA: SOME_DATAFloatPart,
            });
          })
      );

      functions.logger.debug('updated SOME_DATA');
    });

    await Promise.all(promises);
    return null;
  });

Firebase pubsub 功能在模拟器中有效，但在生产中不能立即 returns

Firebase pubsub function works in emulator but not returns immediatly in production

firebase

typescript

google-cloud-pubsub

google-cloud-functions

google-cloud-firestore