MS SQL SUM() 使用多个表并仅添加最后记录的值

Question

我正在尝试添加每台机器的报价小时数。我必须查看三个表才能获得正确的最新数据。我能够获得我需要添加的时间列表。

但是，我尝试了各种方法来使用 SUM() 函数，但它总是给我带来聚合错误。

这是SQL代码：

SELECT 
(SELECT TOP 1 change.hours 
    FROM change WHERE change.id = part.id
    ORDER BY change.timeStamp DESC) as 'Hours'

FROM change 
INNER JOIN part ON (part.id = change.id)
INNER JOIN  completed ON (part.id = completed.id) 

WHERE part.id NOT IN (SELECT completed.id FROM completed WHERE completed.completed = 1) 
and (SELECT TOP 1 change.machine FROM change WHERE part.id = change.id ORDER BY change.timeStamp DESC ) = :machine

GROUP BY change.id, part.id

我基本上需要将每台机器的所有小时相加的单单元格结果。结果将显示在 GUI 上。

结果应该是 机器 1 必须是 12 小时机器2必须是18小时机器 3 必须是 18 小时

表格

部分

id	number	description	job
14	40023-10-100-10-03	Base	40023
15	40023-10-200-10-03	Base	40023
16	40024-10-100-10-01	sensor bracket	40024
17	40024-10-100-10-02	Side	40024
18	40025-10-100-10-01	Conveyor hold	40025
19	40025-10-200-00-01	Part	40025
20	40026-10-400-00-01	Motor Mount	40026
21	40026-10-200-10-10	Delta arms	40026
22	40023-10-200-10-03	Base	40023

改变

id	qty	hours	machine	operator	startTime	stopTime	completed	date	timeStamp
14	0	0	2	2	NULL	NULL	False	NULL	2021-10-28 00:00:00.000
15	0	0	4	3	NULL	NULL	False	NULL	2021-10-28 11:01:41.427
19	0	0	3	1	NULL	NULL	False	NULL	2021-10-28 11:10:50.730
18	0	0	2	3	NULL	NULL	False	NULL	2021-10-28 11:13:46.213
16	3	2.5	2	2	NULL	NULL	False	2021-10-27	2021-10-28 13:41:12.393
16	3	2.5	2	2	NULL	NULL	False	2021-10-27	2021-10-28 13:41:12.393
15	1	9	3	3	NULL	NULL	True	2021-10-29	2021-10-28 21:38:44.883
14	0	0	1	1	NULL	NULL	False	NULL	2021-11-01 10:36:43.223
14	0	0	1	1	NULL	NULL	False	NULL	2021-11-01 10:37:47.153
16	1	0.5	2	2	NULL	NULL	False	2021-11-01	2021-11-01 11:12:06.840
21	0	0	1	1	NULL	NULL	False	NULL	2021-11-01 11:45:30.050
20	0	0	2	3	NULL	NULL	False	NULL	2021-11-10 10:44:00.000
23	0	0	0	0	NULL	NULL	True	2021-11-02	2021-11-02 16:26:18.583
16	1	1	2	2	NULL	NULL	False	2021-11-01	2021-11-01 11:03:44.160
17	0	0	2	2	NULL	NULL	False	NULL	2021-10-28 11:25:03.967
17	0	0	1	1	NULL	NULL	False	NULL	2021-11-01 10:40:36.850
17	0	0	1	1	NULL	NULL	False	NULL	2021-11-01 10:42:56.350
22	0	0	3	2	NULL	NULL	False	NULL	2021-11-02 11:58:08.360
17	0	0	1	2	NULL	NULL	False	NULL	2021-11-01 10:43:44.273
14	0	0	1	1	NULL	NULL	False	NULL	2021-11-01 10:44:23.440
14	0	0	1	1	NULL	NULL	False	NULL	2021-11-02 12:57:06.810

改变

id	hours	qty	machine	operator	notes	rush	timeStamp
14	2	3	2	1		False	2021-10-28 10:48:54.910
15	10	1	3	2		False	2021-10-28 10:49:47.643
16	7	10	2	3	Need material	True	2021-10-28 10:50:33.880
17	4	2	1	1		False	2021-10-28 00:00:00.000
18	5	1	2	2		False	2021-10-28 10:53:15.470
19	8	3	3	3		False	2021-10-28 11:10:50.573
14	3	4	1	1	waiting for mills	False	2021-10-29 08:12:00.000
17	4	2	1	1		True	2021-11-01 10:40:36.707
17	4	2	1	1		True	2021-11-01 10:42:56.150
16	8	10	2	3	Need material	False	2021-11-01 10:43:29.930
17	4	2	1	2		False	2021-11-01 10:43:44.047
14	3	4	1	1		False	2021-11-01 10:44:23.317
20	2	4	2	3		False	2021-11-01 11:44:10.257
21	5	3	1	1	Need material	True	2021-11-01 11:45:29.927
22	10	1	3	2		False	2021-11-02 11:58:08.220
14	3	4	1	1		True	2021-11-02 12:57:06.683
14	4	2	1	1	waiting for bits	False	2021-10-29 00:00:00.000
14	3	4	1	1	wrong mills came. Need to order another ones	False	2021-11-01 10:36:42.997
14	3	4	1	1	wrong mills came. Need to order another ones	False	2021-11-01 10:37:46.983

Answer 1

嗯，我不明白你是如何计算预期结果的，我相信你的查询可以改进很多（如果你更好地解释你的要求，我可以帮助你改进它）。同时，这个查询 returns 你想要什么：

select machine, sum(Hours) Hours from (
SELECT change.machine,
(SELECT TOP 1 change.hours 
    FROM change WHERE change.id = part.id
    ORDER BY change.timeStamp DESC) as 'Hours'

FROM change 
INNER JOIN part ON (part.id = change.id)
INNER JOIN  completed ON (part.id = completed.id) 

WHERE part.id NOT IN (SELECT completed.id FROM completed WHERE completed.completed = 1) 
GROUP BY change.id, part.id, change.machine
) as a 
group by machine

它returns:

machine	Hours
1	12
2	18
3	18

DBFiddle: https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=80ab33a349388896af3ffcb8954c56c9

Answer 2

卡洛斯，干得好。

我能够添加到您的代码中以获得我需要的结果

输入显示的是哪台机器。 :machine 是输入。

SELECT ISNULL((
SELECT sum(Hours)
FROM (SELECT 
        (SELECT TOP 1 change.hours 
            FROM change WHERE change.id = part.id
            ORDER BY change.timeStamp DESC) as 'Hours'
    FROM change 
        INNER JOIN part ON (part.id = change.id)
        INNER JOIN  completed ON (part.id = completed.id) 
    
    WHERE part.id NOT IN (SELECT completed.id FROM completed WHERE completed.completed = 1) 
    and (SELECT TOP 1 change.machine FROM change WHERE part.id = change.id ORDER BY change.timeStamp DESC) = :machine
    
    GROUP BY change.id, part.id) as a), 0)

MS SQL SUM() 使用多个表并仅添加最后记录的值

MS SQL SUM() using multiple tables and adding only last recorded value

sql

sql-server

sum

ignition

表格

部分

改变

改变