python SQL 像运算符需要 return 从 SQL 列表中匹配

Question

我有一个类似的数据框。

Animal
------
Cat
Horse
Mouse

我的 SQL 清单是。

["SELECT * FROM df WHERE Animal LIKE '%og'", "SELECT * FROM df WHERE Animal LIKE '%at'", "SELECT * FROM df WHERE Animal LIKE '%ous'"]

我想要的结果需要是。

Animal  sql
-----------
Cat     %at
Mouse   %ous

我尝试了以下方法并尝试添加一个 JOIN/INSERT 但收效甚微。

from pandasql import sqldf
import pandas as pd

df  = {'Animal': ['Cat', 'Horse', 'Mouse']}
df = pd.DataFrame(df)
searchStrings = ['%og', '%ouse', '%at']

sqls = []
for i in searchStrings:
    j = "SELECT * from df where Animal LIKE '%s'" %(i)
    sqls.append(j)

dfNew = [sqldf(k).drop_duplicates() for k in sqls]
dfNew = pd.concat(dfNew)

谢谢！

Answer 1

使用字典代替列表：

sqls = {i: f"SELECT * FROM df WHERE Animal LIKE '{i}'" for i in searchStrings}

out = pd.concat({key: sqldf(qs) for key, qs in sqls.items()}, names=['sql', None]) \
        .droplevel(1).reset_index().drop_duplicates()

输出：

>>> out
     sql Animal
0  %ouse  Mouse
1    %at    Cat

python SQL 像运算符需要 return 从 SQL 列表中匹配

python SQL like operator needs to return match from list of SQLs

python

sql

pandas

sqldf