我如何包装图像 url 的字幕，以便它引导到另一个屏幕？

Question

我试图让用户点击图片并允许他们获取有关该图片的信息，我该怎么做？我正在考虑在手势检测器中包装字幕（带有图像 url），但出现了一些错误，所以我想知道如何修复此错误。谢谢

   import 'package:flutter/material.dart';

class ProfilePage extends StatefulWidget {
  const ProfilePage({Key? key}) : super(key: key);

  @override
  _ProfilePageState createState() => _ProfilePageState();
}

class _ProfilePageState extends State<ProfilePage> {
  // This holds a list of fiction users
  // You can use data fetched from a database or a server as well
  final List<Map<String, dynamic>> _allHerbs = [
    {
      "id": 1,
      "name": "plant1",
      "urlImage":
          'https://www.southernexposure.com/media/products/originals/sweet-genovese-basil-809aaf7e3d9a3f3fa7ce2f0eb4480e95.jpg'
    },
    {"id": 2, "name": "plant2", "urlImage": ''},
    {"id": 3, "name": "plant3", "urlImage": ''},
    {"id": 4, "name": "plant4", "urlImage": ''},
    {"id": 5, "name": "plant5", "urlImage": ''},
    {"id": 6, "name": "plant6", "urlImage": ''},
    {"id": 7, "name": "plant7", "urlImage": ''},
    {"id": 8, "name": "plant8", "urlImage": ''},
    {"id": 9, "name": "plant9", "urlImage": ''},
    {"id": 10, "name": "plant10", "urlImage": ''},
  ];

  // This list holds the data for the list view
  List<Map<String, dynamic>> _foundHerbs = [];
  @override
  initState() {
    // at the beginning, all users are shown
    _foundHerbs = _allHerbs;
    super.initState();
  }

  // This function is called whenever the text field changes
  void _runFilter(String enteredKeyword) {
    List<Map<String, dynamic>> results = [];
    if (enteredKeyword.isEmpty) {
      // if the search field is empty or only contains white-space, we'll display all users
      results = _allHerbs;
    } else {
      results = _allHerbs
          .where((user) =>
              user["name"].toLowerCase().contains(enteredKeyword.toLowerCase()))
          .toList();
      // we use the toLowerCase() method to make it case-insensitive
    }

    // Refresh the UI
    setState(() {
      _foundHerbs = results;
    });
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: const Text('Herb Search'),
      ),
      body: Padding(
        padding: const EdgeInsets.all(10),
        child: Column(
          children: [
            const SizedBox(
              height: 20,
            ),
            TextField(
              onChanged: (value) => _runFilter(value),
              decoration: const InputDecoration(
                  labelText: 'Search', suffixIcon: Icon(Icons.search)),
            ),
            const SizedBox(
              height: 20,
            ),
            Expanded(
              child: _foundHerbs.isNotEmpty
                  ? ListView.builder(
                      itemCount: _foundHerbs.length,
                      itemBuilder: (context, index) => Card(
                        key: ValueKey(_foundHerbs[index]["id"]),
                        color: Colors.blueAccent,
                        elevation: 4,
                        margin: const EdgeInsets.symmetric(vertical: 10),
                        child: ListTile(
                          leading: Text(
                            _foundHerbs[index]["id"].toString(),
                            style: const TextStyle(fontSize: 24),
                          ),
                          title: Text(_foundHerbs[index]['name']),
                          subtitle: Image.Network('${_foundHerbs[index]["urlImage"]} '),
                        ),
                      ),
                    )
                  : const Text(
                      'No results found',
                      style: TextStyle(fontSize: 24),
                    ),
            ),
          ],
        ),
      ),
    );
  }
}

Answer 1

首先，您不需要使用其他小部件来处理点击事件。 ListTile 已经有 onTap: 回调方法。

其次，您的 subtitle 有两个问题，Image.Network 将是 Image.network 并在 url 部分提供具有额外 space 的路径，或者你可以只使用 likeImage.network( _foundHerbs[index]["urlImage"],),.

ListTile 会像

child: ListTile(
  onTap: () {
    print(_foundHerbs[index].toString());
  },
  leading: Text(
    _foundHerbs[index]["id"].toString(),
    style: const TextStyle(fontSize: 24),
  ),
  title: Text(_foundHerbs[index]['name']),
  subtitle: Container(
    color: Colors.amber,
    child: Image.network(
      '${_foundHerbs[index]["urlImage"]}',
    ),
  )),

我如何包装图像 url 的字幕，以便它引导到另一个屏幕？

How would I wrap the subtitle for the image url so that it leads to another screen?

image

flutter

gesturedetector

swiftui-ontapgesture