如何将一个 link 图像 URL 转换为另一个 URL 以在 flutter 中显示有关第一个 URL 的一些信息？

Question

我正在尝试为我的代码中的每个图像 URL 创建一个 hyperlink 到 link，这样用户就可以被引导到另一个包含图像信息的页面那被点击了。我该怎么做？

import 'package:flutter/material.dart';

class ProfilePage extends StatefulWidget {
  const ProfilePage({Key? key}) : super(key: key);

  @override
  _ProfilePageState createState() => _ProfilePageState();
}

class _ProfilePageState extends State<ProfilePage> {
  // This holds a list of fiction users
  // You can use data fetched from a database or a server as well
  final List<Map<String, dynamic>> _allHerbs = [
    {
      "id": 1,
      "name": "plant1",
      "urlImage":
          'https://www.southernexposure.com/media/products/originals/sweet-genovese-basil-809aaf7e3d9a3f3fa7ce2f0eb4480e95.jpg'
    },
    {"id": 2, "name": "plant2", "urlImage": ''},
    {"id": 3, "name": "plant3", "urlImage": ''},
    {"id": 4, "name": "plant4", "urlImage": ''},
    {"id": 5, "name": "plant5", "urlImage": ''},
    {"id": 6, "name": "plant6", "urlImage": ''},
    {"id": 7, "name": "plant7", "urlImage": ''},
    {"id": 8, "name": "plant8", "urlImage": ''},
    {"id": 9, "name": "plant9", "urlImage": ''},
    {"id": 10, "name": "plant10", "urlImage": ''},
  ];

  // This list holds the data for the list view
  List<Map<String, dynamic>> _foundHerbs = [];
  @override
  initState() {
    // at the beginning, all users are shown
    _foundHerbs = _allHerbs;
    super.initState();
  }

  // This function is called whenever the text field changes
  void _runFilter(String enteredKeyword) {
    List<Map<String, dynamic>> results = [];
    if (enteredKeyword.isEmpty) {
      // if the search field is empty or only contains white-space, we'll display all users
      results = _allHerbs;
    } else {
      results = _allHerbs
          .where((user) =>
              user["name"].toLowerCase().contains(enteredKeyword.toLowerCase()))
          .toList();
      // we use the toLowerCase() method to make it case-insensitive
    }

    // Refresh the UI
    setState(() {
      _foundHerbs = results;
    });
  }

  @override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: const Text('Herb Search'),
      ),
      body: Padding(
        padding: const EdgeInsets.all(10),
        child: Column(
          children: [
            const SizedBox(
              height: 20,
            ),
            TextField(
              onChanged: (value) => _runFilter(value),
              decoration: const InputDecoration(
                  labelText: 'Search', suffixIcon: Icon(Icons.search)),
            ),
            const SizedBox(
              height: 20,
            ),
            Expanded(
              child: _foundHerbs.isNotEmpty
                  ? ListView.builder(
                      itemCount: _foundHerbs.length,
                      itemBuilder: (context, index) => Card(
                        key: ValueKey(_foundHerbs[index]["id"]),
                        color: Colors.blueAccent,
                        elevation: 4,
                        margin: const EdgeInsets.symmetric(vertical: 10),
                        child: ListTile(
                          leading: Text(
                            _foundHerbs[index]["id"].toString(),
                            style: const TextStyle(fontSize: 24),
                          ),
                          title: Text(_foundHerbs[index]['name']),
                          subtitle: Image.Network('${_foundHerbs[index]["urlImage"]} '),
                        ),
                      ),
                    )
                  : const Text(
                      'No results found',
                      style: TextStyle(fontSize: 24),
                    ),
            ),
          ],
        ),
      ),
    );
  }
}

Answer 1

如果我理解你的问题，对于每一个被点击的图片，你都希望被定向到包含该图片信息的另一个页面。

一种解决方法是：

获取的数据可以修改为：{"id": 2, "name": "plant2", "urlImage": '', **"urlInfo" :""**}
既然你想启动一个 url，你可以使用 **url_launcher package** 或一个合适的包，这取决于你想如何访问信息。如果您想在应用程序内访问信息，请使用 WebView 包。

您正在使用 ListTile，因此您可以：使用 url_launcher 包时

 ListTile(
 onTap: () async{
          await launch('${_foundHerbs[index]["urlInfo"]} ');
 },
),

或者像 flutter_webview_plugin 这样的东西，你可以这样做：

ListTile(
onTap: (){
          Navigator.push(
                context,
                MaterialPageRoute(
                  builder: (context) => WebviewScaffold(
      url: '${_foundHerbs[index]["urlInfo"]} ',
      appBar: new AppBar(
        title: new Text("Image Information"),
        withJavascript: true,
      ),
    ),
   ),
  );
},
),

如何将一个 link 图像 URL 转换为另一个 URL 以在 flutter 中显示有关第一个 URL 的一些信息？

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