如何将货币符号添加到我的数组中?

How to add a currency symbol to my array?

目标:

用英镑符号显示我的佣金支付列表。

说明问题是什么:

在显示结果时,它不会打印整个结果,而只是打印 £ 符号。

我试过的:

如您在代码中所见,我尝试将数组转换为字符串(将其放入自己的变量中),然后向其添加货币符号 (£) 并要求调用 commission2。但是,它没有显示。

输出:

Name         Id           Houses Sold  Commission  
£1000

ki           2            2            £  

(1000英镑只是为了说明数据确实存在,但是在列表中打印时不知为何没有显示...)

所需输出:

Name         Id           Houses Sold  Commission  

ki           2            2            £1000 

我已经花了好几个小时了,所以如果有任何帮助,我们将不胜感激!

错误代码:

def print_entered_info(names, ids, num_sold_houses):
print()
row_width = 12
comission_per_house = 500
header = ['Name', 'Id', 'Houses Sold', 'Commission']
print(' '.join(f'{h:<{row_width}}' for h in header))
commission = [n * comission_per_house for n in num_sold_houses] 
commission2 = commission
commission2 = ''.join(str(e) for e in commission)
commission2= "£" + commission2
print(commission2)
for values in zip(*[names, ids, num_sold_houses, commission2]):
    print()
    print(' '.join(f'{v:<{row_width}}' for v in values))

我的完整代码:

def get_int_input(prompt: str) -> int:
    num = -1
    while True:
        try:
            num = int(input(prompt))
            break
        except ValueError:
            print('Error: Enter an integer, try again...')
    return num

def get_yes_no_input(prompt: str) -> bool:
    allowed_responses = {'y', 'yes', 'n', 'no'}
    user_input = input(prompt).lower()
    while user_input not in allowed_responses:
        user_input = input(prompt).lower()
    return user_input[0] == 'y'

names = []
ids = []
num_sold_houses= []
def get_single_employee_info(names, ids, num_sold_houses):
 names.append(input('What is the employee\'s name?: '))
 ids.append(get_int_input('What is the employee\'s id?: '))
 num_sold_houses.append(get_int_input('How many houses did the employee sell?: '))

def get_houses_sold_info(names, ids, num_sold_houses):
    get_single_employee_info(names, ids, num_sold_houses)
    add_another_employee = get_yes_no_input('Add another employee [yes/no]?: ')
    while add_another_employee:
        get_single_employee_info(names, ids, num_sold_houses)
        add_another_employee = get_yes_no_input(
            'Add another employee [yes/no]?: ')

def print_entered_info(names, ids, num_sold_houses):
    print()
    row_width = 12
    comission_per_house = 500
    header = ['Name', 'Id', 'Houses Sold', 'Commission']
    print(' '.join(f'{h:<{row_width}}' for h in header))
    commission = [n * comission_per_house for n in num_sold_houses] 
    commission2 = commission
    commission2 = ''.join(str(e) for e in commission)
    commission2= "£" + commission2
    print(commission2)
    for values in zip(*[names, ids, num_sold_houses, commission2]):
        print()
        print(' '.join(f'{v:<{row_width}}' for v in values))
    print()   
    total_commission = sum(commission)
    print(f'Total Commission: £{total_commission}.00 (before bonus)')
    print()
    bonus = max(commission)
    if bonus >= max(commission):
     bonus = bonus*0.15
     bonus = (int(max(commission)) + bonus)
     commission = bonus

    print("The person at the top of ranking gets: " + "£" + str(commission)+"0") 
    print()
    rankings = sorted(zip(num_sold_houses, names), reverse=True)
    print('Ranking:')
    for houses_sold, name in rankings:
        print(f'{name} - {houses_sold}')

def main() -> None:
    print('Houses Sold Tracker')
    print('===================')
    names, ids, num_houses_sold = [], [], []
    get_houses_sold_info(names, ids, num_houses_sold)
    print_entered_info(names, ids, num_houses_sold)

if __name__ == '__main__':
    main() 

换掉

commission2 = ''.join(str(e) for e in commission)

commission2 = ["£" + str(e) for e in commission]

并删除它下面的行。您的 ''.join 正在采用 2 个列表元素并将它们强制为单个字符串,这不是您想要的逻辑。您需要 commission2 变量的列表输出,因此我们创建一个列表并将字符串化值连同货币符号附加到它。

输出:

Name         Id           Houses Sold  Commission  

Kevin        1            3            £1500       

Stacey       2            5            £2500       

Total Commission: £4000.00 (before bonus)

The person at the top of ranking gets: £2875.00

Ranking:
Stacey - 5
Kevin - 3