帮我理解 session api Gatling
Helping me understand session api Gatling
我是加特林新手
我正在尝试循环 json 响应,找到我正在寻找的国家代码,并获取与该国家代码对应的 ID。
示例算法:
list.foreach( value => { if (value.coutrycode == "PL") 然后存储 value.id })
加特林机:
def getOffer() = {
exec(
http("GET /offer")
.get("/offer")
.check(status.is(Constant.httpOk))
.check((bodyString.exists),
jsonPath("$[*]").ofType[Map[String,Any]].findAll.saveAs("offerList")))
.foreach("${offerList}", "item"){
exec(session => {
val itemMap = session("item").as[Map[String,Any]]
val countryCodeId = itemMap("countryCode")
println("****" + countryCodeId)
// => print all the country code on the list
if (countryCodeId =="PL"){ // if statement condition
println("*************"+ itemMap("offerd")); // print the id eg : "23"
session.set("offerId", itemMap("offerId")); // set the id on the session
}
println("$$$$$$$$$$$$$$" + session("offerId")) // verify that th session contains the offerId but is not
session
})
}
}
当我尝试打印会话(“offerId”)时,打印的是“item”而不是 offerId。
我查看了文档,但不理解这种行为。你能给我解释一下吗?
Session instances are immutable!
Why is that so? Because Sessions are messages that are dealt with in a
multi-threaded concurrent way, so immutability is the best way to deal
with state without relying on synchronization and blocking.
A very common pitfall is to forget that set and setAll actually return
new instances.
val session: Session = ???
// wrong usage
session.set("foo", "FOO") // wrong: the result of this set call is just discarded
session.set("bar", "BAR")
// proper usage
session.set("foo", "FOO").set("bar", "BAR")
所以你想要的是:
val newSession =
if (countryCodeId =="PL"){ // if statement condition
println("*************"+ itemMap("offerd")); // print the id eg : "23"
session.set("offerId", itemMap("offerId")); // set the id on the session
} else {
session
}
// verify that the session contains the offerId
println("$$$$$$$$$$$$$$" + newSession("offerId").as[String])
newSession
我是加特林新手 我正在尝试循环 json 响应,找到我正在寻找的国家代码,并获取与该国家代码对应的 ID。 示例算法: list.foreach( value => { if (value.coutrycode == "PL") 然后存储 value.id })
加特林机:
def getOffer() = {
exec(
http("GET /offer")
.get("/offer")
.check(status.is(Constant.httpOk))
.check((bodyString.exists),
jsonPath("$[*]").ofType[Map[String,Any]].findAll.saveAs("offerList")))
.foreach("${offerList}", "item"){
exec(session => {
val itemMap = session("item").as[Map[String,Any]]
val countryCodeId = itemMap("countryCode")
println("****" + countryCodeId)
// => print all the country code on the list
if (countryCodeId =="PL"){ // if statement condition
println("*************"+ itemMap("offerd")); // print the id eg : "23"
session.set("offerId", itemMap("offerId")); // set the id on the session
}
println("$$$$$$$$$$$$$$" + session("offerId")) // verify that th session contains the offerId but is not
session
})
}
}
当我尝试打印会话(“offerId”)时,打印的是“item”而不是 offerId。 我查看了文档,但不理解这种行为。你能给我解释一下吗?
Session instances are immutable!
Why is that so? Because Sessions are messages that are dealt with in a multi-threaded concurrent way, so immutability is the best way to deal with state without relying on synchronization and blocking.
A very common pitfall is to forget that set and setAll actually return new instances.
val session: Session = ???
// wrong usage
session.set("foo", "FOO") // wrong: the result of this set call is just discarded
session.set("bar", "BAR")
// proper usage
session.set("foo", "FOO").set("bar", "BAR")
所以你想要的是:
val newSession =
if (countryCodeId =="PL"){ // if statement condition
println("*************"+ itemMap("offerd")); // print the id eg : "23"
session.set("offerId", itemMap("offerId")); // set the id on the session
} else {
session
}
// verify that the session contains the offerId
println("$$$$$$$$$$$$$$" + newSession("offerId").as[String])
newSession