使用正则表达式在 redshift 中用逗号和引号分割字符串
String split with comma and quotes in redshift using Regex
我在 redshift table 中有一个字符串列，例如：
String
["0","0","5","0","0","0","0","0","0","0","0","0","0","0","0","0","0"]
["0","0","0","8","30","0","0","0","0"]
["0","0"]
我想拆分字符串列以在 6 个不同的列中获取字符串的前 6 个字符，如下所示
String
Col1
Col2
Col3
Col4
Col5
Col6
["0","0","5","10","20","30","0","0","0","0","0","0","0","0","0","0","0"]
0
0
5
10
20
30
["0","0","0","8","30","0","0","0","0"]
0
0
0
8
30
0
["0","0"]
0
0
我不熟悉 Redshift 和正则表达式概念。任何帮助都会有很大帮助。
尝试 REGEXP_SUBSTR:
select
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 1) as col1,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 2) as col2,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 3) as col3,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 4) as col4,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 5) as col5,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 6) as col6
from mytable;
我在 redshift table 中有一个字符串列，例如：
String
["0","0","5","0","0","0","0","0","0","0","0","0","0","0","0","0","0"]
["0","0","0","8","30","0","0","0","0"]
["0","0"]
我想拆分字符串列以在 6 个不同的列中获取字符串的前 6 个字符，如下所示
| String | Col1 | Col2 | Col3 | Col4 | Col5 | Col6 |
|---|---|---|---|---|---|---|
| ["0","0","5","10","20","30","0","0","0","0","0","0","0","0","0","0","0"] | 0 | 0 | 5 | 10 | 20 | 30 |
| ["0","0","0","8","30","0","0","0","0"] | 0 | 0 | 0 | 8 | 30 | 0 |
| ["0","0"] | 0 | 0 |
我不熟悉 Redshift 和正则表达式概念。任何帮助都会有很大帮助。
尝试 REGEXP_SUBSTR:
select
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 1) as col1,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 2) as col2,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 3) as col3,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 4) as col4,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 5) as col5,
REGEXP_SUBSTR(mystr, '[0-9]+', 1, 6) as col6
from mytable;