关于使用多个 SQL GROUP BY 语句的问题

Question

所以最终我试图显示一个投手在我的棒球联赛中获得 Cy Young 奖的总次数，然后是他们赢得它的赛季年份，但按联盟名称排序，因为一个投手可以在同一年获得不同联赛的奖项。

这就是我尝试显示数据的方式：安德鲁·琼斯 (4) - 2021、2020 (18+)； 2021 年（28 岁以上）； 2021 (38+)，所以我需要Seasons列吐出这样的数据：2021, 2020 (18+); 2021 年（28 岁以上）； 2021 (38+)

我有 3 个 mySQL 桌（赛季，联赛，CY_YOUNG）：

联赛

| LEAGUE_ID | LEAGUE_NAME   |
| -------- | -------------- |
| 1        | 18+            |
| 2        | 28+            |
| 3        | 38+            |
| 4        | 48+            |

四季

| SEASON_ID| LEAGUE_ID      | SEASON_YEAR |
| --------   | -------------| ----------- |
| 332        | 1            |   2021    |
| 333        | 2            |   2021    |
| 334        | 3            |   2021    |
| 335        | 4            |   2021    |
| 300        | 1            |   2020    |
| 301        | 2            |   2020    |
| 302        | 3            |   2020    |
| 303        | 4            |   2020    |

CY_YOUNG

| SEASON_ID  | PLAYER_NAME    | PLACE     |
| --------   | -------------- | ----------|
| 332        | Andrew Jones   |   1       |
| 332        | Mike Smith     |   2       |
| 333        | Andrew Jones   |   1       |
| 333        | Jacob Grimes   |   2       |
| 334        | Andrew Jones   |   1       |
| 334        | Travis Deane   |   2       |
| 300        | Andrew Jones   |   1       |

这是我当前的 SQL 查询：


   SELECT PLAYER_NAME, COUNT(ID) AS TotalWins, GROUP_CONCAT(DISTINCT CONCAT(S.SEASON_YEAR,' (',L.LEAGUE_NAME) 
   ORDER BY S.SEASON_YEAR DESC SEPARATOR '), ') AS Seasons
   FROM CY_YOUNG
   JOIN SEASONS S ON S.SEASON_ID = CY_YOUNG.SeasonID
   JOIN LEAGUES L ON L.LEAGUE_ID = S.LEAGUE_ID
   WHERE CY_YOUNG.Place = 1
   GROUP BY PLAYER_NAME
   HAVING TotalWins > 1
   ORDER BY TotalWins DESC;

Seasons栏目目前是这样吐槽的：2021（18+），2020（18+），2021（38+）不过我愿意像这样吐槽：2021、2020（18+）； 2021 年（28 岁以上）； 2021 (38+)。我知道我很接近所以任何帮助都将不胜感激！

Answer 1

您需要 2 个聚合级别：

SELECT PLAYER_NAME, 
       SUM(counter) AS TotalWins,  
       GROUP_CONCAT(years, ' (', LEAGUE_NAME, ')' ORDER BY LEAGUE_NAME, years) AS Seasons
FROM (
  SELECT PLAYER_NAME, L.LEAGUE_NAME,
         COUNT(*) counter,
         GROUP_CONCAT(S.SEASON_YEAR ORDER BY S.SEASON_YEAR DESC) AS years
  FROM CY_YOUNG C
  JOIN SEASONS S ON S.SEASON_ID = C.SEASON_ID
  JOIN LEAGUES L ON L.LEAGUE_ID = S.LEAGUE_ID
  WHERE C.Place = 1
  GROUP BY C.PLAYER_NAME, L.LEAGUE_NAME
) t  
GROUP BY PLAYER_NAME
HAVING TotalWins > 1
ORDER BY TotalWins DESC;

参见demo。

关于使用多个 SQL GROUP BY 语句的问题

Question on using multiple SQL GROUP BY statements

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