python 计算嵌套字典中出现的值

Question

我无法找到计算值的解决方案。

data = {"members": {
    "1": {
        "name": "burek",            
        },
        "status": {
            "description": "Online",
            "state": "Busy",
            "color": "green",
        },
        "position": "seller"
    },{
    "2": {
        "name": "pica",         
        },
        "status": {
            "description": "Offline",
            "state": "Idle",
            "color": "red",
        },
        "position": "waiting"
    },{
    "3": {
        "name": "strucko",          
        },
        "status": {
            "description": "Online",
            "state": "Busy",
            "color": "green",
        },
        "position": "backside"
    }}

现在我可以数钥匙了：

def count(d, k):
 return (k in d) + sum(count(v, k) for v in d.values() if isinstance(v, dict))

但是在想出计算值的方法时遇到了很多麻烦。

print(count(data, 'Online'))

我希望结果为 2。

Answer 1

一种方法：

def count(d, k):
    current = 0
    for di in d.values():
        if isinstance(di, dict):
            current += count(di, k)
        elif k == di:
            current += 1
    return current


res = count(data, "Online")
print(res)

输出

设置

data = {
  "members": {
    "1": {
      "name": "burek",
      "status": {
        "description": "Online",
        "state": "Busy",
        "color": "green"
      },
      "position": "seller"
    },
    "2": {
      "name": "pica",
      "status": {
        "description": "Offline",
        "state": "Idle",
        "color": "red"
      },
      "position": "waiting"
    },
    "3": {
      "name": "strucko",
      "status": {
        "description": "Online",
        "state": "Busy",
        "color": "green"
      },
      "position": "backside"
    }
  }
}

python 计算嵌套字典中出现的值

python counting occurrences value in nested dictionary

python

dictionary

nested

count