获取数组内部数组的问题
Porblem on Getting Array Inside of Array
我在数组内部的对象上遇到问题,我只想将其显示为数组。
data1
const data1 = [
{
"id": "01",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "fruits"
}
},
{
"id": "02",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "things"
}
}
]
预期输出
const final= [
{
"data": "fruits"
},
{
"data": "things"
}
]
代码
const final = data.map((data) => { ...data})
通过数组映射并提取其details
属性:
const data1 = [
{
"id": "01",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "fruits"
}
},
{
"id": "02",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "things"
}
}
]
const res = data1.map(e => e.details)
console.log(res)
map
遍历数组并 return 使用细节 属性 的新对象 。如果您不 return 一个新对象,您的新数组仍将包含对原始数组中对象的引用。因此,如果您更改原始数组中 属性 的值,该更改也会反映在新数组中,您可能不希望这种情况发生。
const data1=[{id:"01",info:"fefef",sub:"hieei",details:{data:"fruits"}},{id:"02",info:"fefef",sub:"hieei",details:{data:"things"}}];
// Make sure you return a copy of the
// details object otherwise if you change the details
// of the original objects in the array
// the new mapped array will carry those object changes
// because the array objects will simply references to the old objects
const out = data1.map(obj => {
return { ...obj.details };
});
console.log(out);
使用 map
和解构将简化。
const data1 = [
{
id: "01",
info: "fefef",
sub: "hieei",
details: {
data: "fruits",
},
},
{
id: "02",
info: "fefef",
sub: "hieei",
details: {
data: "things",
},
},
];
const res = data1.map(({ details: { data } }) => ({ data }));
console.log(res);
// if you just need the details object
const res2 = data1.map(({ details }) => details);
console.log(res2);
我在数组内部的对象上遇到问题,我只想将其显示为数组。
data1
const data1 = [
{
"id": "01",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "fruits"
}
},
{
"id": "02",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "things"
}
}
]
预期输出
const final= [
{
"data": "fruits"
},
{
"data": "things"
}
]
代码
const final = data.map((data) => { ...data})
通过数组映射并提取其details
属性:
const data1 = [
{
"id": "01",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "fruits"
}
},
{
"id": "02",
"info": "fefef",
"sub": "hieei",
"details": {
"data": "things"
}
}
]
const res = data1.map(e => e.details)
console.log(res)
map
遍历数组并 return 使用细节 属性 的新对象 。如果您不 return 一个新对象,您的新数组仍将包含对原始数组中对象的引用。因此,如果您更改原始数组中 属性 的值,该更改也会反映在新数组中,您可能不希望这种情况发生。
const data1=[{id:"01",info:"fefef",sub:"hieei",details:{data:"fruits"}},{id:"02",info:"fefef",sub:"hieei",details:{data:"things"}}];
// Make sure you return a copy of the
// details object otherwise if you change the details
// of the original objects in the array
// the new mapped array will carry those object changes
// because the array objects will simply references to the old objects
const out = data1.map(obj => {
return { ...obj.details };
});
console.log(out);
使用 map
和解构将简化。
const data1 = [
{
id: "01",
info: "fefef",
sub: "hieei",
details: {
data: "fruits",
},
},
{
id: "02",
info: "fefef",
sub: "hieei",
details: {
data: "things",
},
},
];
const res = data1.map(({ details: { data } }) => ({ data }));
console.log(res);
// if you just need the details object
const res2 = data1.map(({ details }) => details);
console.log(res2);