如何在没有 unicode 转义序列 Swift 的情况下获得 JSON 响应

Question

我正在尝试以正确的形式获取数据，这是我的请求示例：

var request = URLRequest(url: url)
request.httpMethod = "GET"
request.allHTTPHeaderFields = [
    "Content-Type": "http",
    "Authorization": token
]        
let session = URLSession.shared
session.dataTask(with: request) { data, response, error in

    guard let data = data else {
        completion(.failure(.invalidData))
        return
    }

    do {
        if let string = String(data: data, encoding: .utf8) { print(string) }
        let json = try JSONSerialization.jsonObject(with: data, options: [])
        print(json)
        completion(.failure(.invalidURL))
    }
    catch {
        completion(.failure(.decodingProblem))
    }
}.resume()

在那个请求之后，我总是得到 JSON 结果，就像下一个一样。但我想得到没有unicode序列的正确文本

{
    "result": {
        "id": 2,
        "write_date": "2021-10-05T08:46:53.945082",
        "name": "\u041e\u0432\u0430\u0434\u0447\u0443\u043a",
        "x_phone": "+380999999999",
        "number_policy": "\u0422\u0435\u0441\u0442",
        "client_email": "test@it.com.ua",
        "x_sk_phone1": "+380999999999",
        "x_manager1": "\u041c\u0435\u043d\u0435\u0434\u0436\u0435\u0440 1",
        "x_u_phone": "45454544",
        "x_u_email": "app@it.com.ua",
        "x_u_phone_man1": "123456789",
        "x_street": "\u0456\u0432\u0441\u044c\u043a\u0430, 29",
        "x_street2": "\u043b\u0456\u0432\u0441\u044c\u043a\u0438\u0439\u00bb, 5 \u044d\u0442\u0430\u0436",
        "x_city": "\u041a\u0438\u0457\u0432",
        "x_com_street": "\u043e\u0447\u0438\u0446\u044c\u043a\u0430,44",
        "x_ost_zab": "\u0422\u0430\u043a",
        "x_zab_v_obos": "\u0422\u0430\u043a",
        "x_zab_v_rem": "\u041d\u0456",
        "x_travma": "\u0422\u0430\u043a",
        "x_sd_1": "100%",
        "x_sd_2": "\u0422\u0430\u043a",
        "x_sd_3": "\u0422\u0430\u043a",
        "x_sp_1": "\u0422\u0430\u043a, \u0432 \u043c\u0435\u0436\u0430\u0445 \u043b\u0456\u043c\u0456\u0442\u0443",
        "x_dop_1": "\u0422\u0430\u043a",
        "x_info": "\u0422\u0435\u0441\u0442\u043e\u0432\u0438\u0439 \u0437\u0430\u043f\u0438\u0441 \u0434\u043b\u044f \u0432\u0456\u0434\u043e\u0431\u0440\u0430\u0436\u0435\u043d\u043d\u044f \u0443 \u043f\u0440\u043e\u0433\u0440\u0430\u043c\u043c\u0456 \u043a\u043b\u0456\u0435\u043d\u0442\u0430 \u0432 \u043c\u043e\u0431\u0456\u043b\u044c\u043d\u043e\u043c\u0443 \u0434\u043e\u0434\u0430\u0442\u043a\u0443",
        "x_limit_1": "300 000",
        "x_limit_other": "Some"
    }
}

所以我想获得没有 unicode 序列的正确文本。

Answer 1

您的 JSON 字符串有一些问题。使用 \U 时，它应该发送 4 个字节（8 个十六进制字符），但它只发送 2 个字节（4 个十六进制字符）。如果您可以控制正在 returned 的内容，最简单的解决方案是 return \u 而不是 \U，这是 2 个字节的正确 unicode 转义，否则您将不得不进行一些字符串操作并应用解码 json:

之前的字符串转换

let jsonData = Data(#"{"x_city":"\U041a\U0438\U0457\U0432"}"#.utf8)
let jsonString = String(data: jsonData, encoding: .utf8) ?? ""
let cleanedData = Data(
    jsonString
    .replacingOccurrences(of: #"\U"#, with: #"\u"#)
    .applyingTransform(.init("Hex-Any"), reverse: false)!
    .utf8
)
struct Response: Codable {
    let xCity: String
}
do {
    let decoder = JSONDecoder()
    decoder.keyDecodingStrategy = .convertFromSnakeCase
    let response = try decoder.decode(Response.self, from: cleanedData)
    
    print(response)  // Response(xCity: "Київ")
} catch {
    print(error)
}

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