MySQL 未从 NOT IN 函数返回值

Question

我目前正在尝试编写一个查询，以显示至少有 5 个订单的客户和没有订单的客户。订单在他们自己的 table 中被跟踪，为了找到订单为 0 的客户，我们必须找到不在订单中的客户。下面是我尝试使用的查询，它 returns 同一个客户 5 次零订单。

with t1 as
 (select o.customerNumber, c.customerName, count(o.orderNumber) as FiveOrders
 from orders o join customers c on (o.customerNumber = c.customerNumber)
 group by o.customerNumber having count(o.orderNumber) = 5),
 t2 as
 (select distinct o.customerNumber, c.customerName, count(o.orderNumber) as NoOrders
 from orders o join customers c on (o.customerNumber = c.customerNumber)
 group by c.customerNumber not in(select customerNumber from orders))
 select distinct t1.customerNumber as FiveOrderNumber, t1.customerName as FiveOrderName,
 t2.customerNumber as NoOrderNumber, t2.customerName as NoOrderName
 from t1 join t2
 order by NoOrderName;

感谢任何帮助，谢谢！

Answer 1

如果错误只在第二个table到，我想是在使用之后 having with condition NOT IN 没有任何逻辑比较，我认为您可以轻松获得想要的结果，例如：

select distinct customerNumber, customerName, "0" as NoOrders 
from customers 
where customerNumber not in (Select customerNumber from orders)

如果 group by 很重要，您可以像在代码中一样使用它。

Answer 2

Zero或five可与LEFT JOIN

一起计算

select c.customerNumber, max(c.customerName) customerName, count(o.orderNumber) as FiveOrdersOrZero
from customers c
left join orders o on o.customerNumber = c.customerNumber
group by c.customerNumber 
having count(o.orderNumber) in ( 0, 5 )
order by FiveOrdersOrZero

MySQL 未从 NOT IN 函数返回值

MySQL not returning values from NOT IN function

mysql

notin