当存在 WITH 语句时，WHERE IN (SELECT) 语句中断查询

Question

这非常有效：

SELECT qaer_name, 
       AVG(Minutes(QA_Time)) AS avg_minutes, 
       COUNT(Zendesk_URL) AS num_tickets
FROM zendeskData
WHERE qaer_name IN (SELECT Name FROM qaers)
AND tags LIKE '%cosmetic%'                    
AND CAST(sub_to_qa_date AS DATE) >= CAST('${new Date('2021-11-10')}' AS DATE)
GROUP BY qaer_name

但这会因错误而中断：TypeError: Cannot read property '0' of undefined

WITH cosmetic AS (
  SELECT qaer_name, 
         AVG(Minutes(QA_Time)) AS avg_minutes, 
         COUNT(Zendesk_URL) AS num_tickets
  FROM zendeskData
  WHERE qaer_name IN (SELECT Name FROM qaers)
  AND tags LIKE '%cosmetic%'                    
  AND CAST(sub_to_qa_date AS DATE) >= CAST('${new Date('2021-11-10')}' AS DATE)
  GROUP BY qaer_name
)
SELECT * FROM cosmetic

这个没有报错（但没有做我想要的过滤）：

WITH cosmetic AS (
  SELECT qaer_name, 
         AVG(Minutes(QA_Time)) AS avg_minutes, 
         COUNT(Zendesk_URL) AS num_tickets
  FROM zendeskData
  --WHERE qaer_name IN (SELECT Name FROM qaers)
  WHERE tags LIKE '%cosmetic%'                    
  AND CAST(sub_to_qa_date AS DATE) >= CAST('${new Date('2021-11-10')}' AS DATE)
  GROUP BY qaer_name
)
SELECT * FROM cosmetic

但是，这个确实给出了同样的错误：TypeError: Cannot read property '0' of undefined

WITH cosmetic AS (
  SELECT qaer_name, 
         AVG(Minutes(QA_Time)) AS avg_minutes, 
         COUNT(Zendesk_URL) AS num_tickets
  FROM zendeskData
  WHERE tags LIKE '%cosmetic%'                    
  AND CAST(sub_to_qa_date AS DATE) >= CAST('${new Date('2021-11-10')}' AS DATE)
  GROUP BY qaer_name
)
SELECT * 
FROM cosmetic
WHERE qaer_name IN (SELECT Name FROM qaers)

为什么 WHERE IN (SELECT) 语句仅在存在 WITH 语句时中断它？

编辑：这也给出了同样的错误。

let data = Database.alasql(`
  ;WITH cosmetic AS (
    SELECT qaer_name, 
          AVG(Minutes(QA_Time)) AS avg_minutes, 
          COUNT(Zendesk_URL) AS num_tickets
    FROM zendeskData z
    WHERE EXISTS (SELECT 1 FROM qaers q WHERE z.qaer_name = q.Name) 
    AND tags LIKE '%cosmetic%'                    
    AND CAST(sub_to_qa_date AS DATE) >= CAST('${new Date('2021-11-10')}' AS DATE)
    GROUP BY qaer_name
  )
  SELECT * 
  FROM cosmetic
`);
Logger.log(data);

Answer 1

我不知道为什么我原来的方法不起作用，但我想出了一个变通办法。

除了制作 qaers table，然后在以后的查询中选择 table，我的替代方法是制作 table 一个 JS 数组，然后传递将其格式化为列表的查询。

这给出了我正在寻找的正确结果，因为它允许我使用名称列表和 WITH 语句，当我使查询变得更复杂时，这是必需的。

let qaers = Database.alasql(`
  SELECT MATRIX Name 
  FROM annotatorData 
  WHERE Pod_Number = 'QA'
`);

let data = Database.alasql(`
  WITH cosmetic AS (
    SELECT qaer_name, 
          AVG(Minutes(QA_Time)) AS avg_minutes, 
          COUNT(Zendesk_URL) AS num_tickets
    FROM zendeskData
    WHERE qaer_name IN ('${qaers.join("','")}')
    AND tags LIKE '%cosmetic%'                    
    AND CAST(sub_to_qa_date AS DATE) >= CAST('${new Date('2021-11-10')}' AS DATE)
    GROUP BY qaer_name
  )
  SELECT * 
  FROM cosmetic
`)

当存在 WITH 语句时，WHERE IN (SELECT) 语句中断查询

WHERE IN (SELECT) statement breaks query, when there is a WITH statement present

sql

google-apps-script

alasql