BeautifulSoup

Question

感谢任何帮助！使用下面的示例 XML 文件，我得到了不正确的输出。

Incorrect output: 
Emp_F_Name: Jill
Emp_M_Name: H
Emp_L_Name: Jones

Desired output:
Emp_F_Name: Jill
Emp_M_Name: None or NULL
Emp_L_Name: Jones

我不确定为什么 find_next 函数会超出声明的属性（员工）。

   <?xml version="1.0" encoding="utf-8"?>
    <org value="Tech">
    <employee>
    <name>
    <family>Jones</family>
    <given>Jill</given>
    </name>
    </employee>
    <manager>
    <name>
    <family>Fisher</family>
    <given>Junior</given>
    <given>H</given>
    </name>
    </manager>
    </org>

这是我正在使用的代码。

employee = soup.find("employee")

for i in employee.find_all('name'):
    fname = employee.find('given')
    print("Emp_F_Name: ", fname.get_text())
    
    mname = fname.find_next('given')
    print("Emp_M_Name: ", mname.get_text())
    
    lname = employee.find('family')
    print("Emp_L_Name: ", lname.get_text())

当我运行相同的代码但对于经理来说，它似乎有效。

manager = soup.find("manager")

Answer 1

如果结构几乎相同，可以尝试'find_all()'所有given的元素，检查是否只有一两个。

given= i.find_all('given')
fname = given[0]
print("Emp_F_Name: ", fname.get_text())
    
mname = given[1].get_text() if len(given) > 1 else None
print("Emp_M_Name: ", mname)

认为没有必要迭代 employee 但如果是这样，您应该使用 i

例子

import requests
from bs4 import BeautifulSoup

xml='''<?xml version="1.0" encoding="utf-8"?>
    <org value="Tech">
    <employee>
    <name>
    <family>Jones</family>
    <given>Jill</given>
    </name>
    </employee>
    <manager>
    <name>
    <family>Fisher</family>
    <given>Junior</given>
    <given>H</given>
    </name>
    </manager>
    </org>'''

soup = BeautifulSoup(xml, 'lxml')

employee = soup.find("employee")

for i in employee.find_all('name'):
    given= i.find_all('given')
    fname = given[0]
    print("Emp_F_Name: ", fname.get_text())
    
    mname = given[1].get_text() if len(given) > 1 else None
    print("Emp_M_Name: ", mname)
    
    lname = i.find('family')
    print("Emp_L_Name: ", lname.get_text())

输出

Emp_F_Name:  Jill
Emp_M_Name:  None
Emp_L_Name:  Jones

另类

将 employee 隔离为单独的树以与 find_next() 一起操作：

employee = BeautifulSoup(str(soup.find("employee")), 'lxml')

for i in employee.find_all('name'):
    fname = i.find('given')
    print("Emp_F_Name: ", fname.get_text())
    
    mname = fname.find_next('given').get_text() if fname.find_next('given') else None
    print("Emp_M_Name: ", mname)
    
    lname = i.find('family')
    print("Emp_L_Name: ", lname.get_text())

Answer 2

使用XML解析器：（不需要任何外部库）

import xml.etree.ElementTree as ET


xml = '''<?xml version="1.0" encoding="UTF-8"?>
<org value="Tech">
   <employee>
      <name>
         <family>Jones</family>
         <given>Jill</given>
      </name>
   </employee>
   <manager>
      <name>
         <family>Fisher</family>
         <given>Junior</given>
         <given>H</given>
      </name>
   </manager>
</org>'''



attrs = {'Emp_F_Name':'given',
         'Emp_L_Name':'family',
         'Emp_M_Name': None}

root = ET.fromstring(xml)
name = root.find('.//name')
for k,v in attrs.items():
  print(f'{k}: {name.find(v).text if v else None}')

输出

Emp_F_Name: Jill
Emp_L_Name: Jones
Emp_M_Name: None

BeautifulSoup - xml - find_next：限制为一个属性

BeautifulSoup - xml - find_next: limiting to one attribute

python

arrays

xml

attributes

例子

输出

另类