Gremlin 将所有返回的边及其顶点分组

Question

我是 Tinker pop 的 gremlin 初学者。我有一张图表，其中一道菜有多个 inE("serves") 来自餐厅：

在这些餐厅中，我只想要两家位置为“卡拉奇”的餐厅。这些都是：

为此，我编写了查询并且它运行良好：

g.V(26).as("cui").inE("serves").outV().hasLabel("restaurant").has("location", "karachi").as("rest")

我想要的是一个 gremlin 查询，它获取这些餐馆的 inE("reviews") 并以这种方式调整数据。

[
"restaurant" : // info related to restaurant,
"reviews": [{array of reviews}]
]

我试过这个脚本：

 g.V(26).as("cui").inE("serves").outV().hasLabel("restaurant").has("location", "karachi").as("rest").where(__.inE("review").has("value",is(gte(2)))).inE("review").order().by("value", desc).as("rev").select("rest","rev").by(elementMap())

但它 returns 此结构中每个评级的数据数组：

["rest": {}, "rating:" {}],
["rest": {}, "rating:" {}],


==>{rest={id=54, label=restaurant, name=restaurant5, location=karachi}, rev={id=67, label=review, IN={id=54, label=restaurant}, OUT={id=9, label=user}, upvotes=3, rated_at=Tue Nov 16 22:13:58 PKT 2021, downvotes=1, value=12}}
==>{rest={id=60, label=restaurant, name=restaurant7, location=karachi}, rev={id=69, label=review, IN={id=60, label=restaurant}, OUT={id=6, label=user}, upvotes=4, rated_at=Tue Nov 16 22:16:45 PKT 2021, downvotes=3, value=5}}
==>{rest={id=60, label=restaurant, name=restaurant7, location=karachi}, rev={id=71, label=review, IN={id=60, label=restaurant}, OUT={id=9, label=user}, upvotes=1, rated_at=Tue Nov 16 22:16:45 PKT 2021, downvotes=5, value=5}}
==>{rest={id=12, label=restaurant, name=restaurant1, location=karachi}, rev={id=41, label=review, IN={id=12, label=restaurant}, OUT={id=0, label=user}, upvotes=8, rated_at=Tue Nov 16 21:49:07 PKT 2021, downvotes=4, value=4}}
==>{rest={id=54, label=restaurant, name=restaurant5, location=karachi}, rev={id=65, label=review, IN={id=54, label=restaurant}, OUT={id=6, label=user}, upvotes=4, rated_at=Tue Nov 16 22:12:57 PKT 2021, downvotes=1, value=4}}
==>{rest={id=12, label=restaurant, name=restaurant1, location=karachi}, rev={id=40, label=review, IN={id=12, label=restaurant}, OUT={id=3, label=user}, upvotes=8, rated_at=Tue Nov 16 21:49:07 PKT 2021, downvotes=4, value=3.7}}
==>{rest={id=60, label=restaurant, name=restaurant7, location=karachi}, rev={id=70, label=review, IN={id=60, label=restaurant}, OUT={id=0, label=user}, upvotes=5, rated_at=Tue Nov 16 22:16:45 PKT 2021, downvotes=2, value=3}}
==>{rest={id=54, label=restaurant, name=restaurant5, location=karachi}, rev={id=68, label=review, IN={id=54, label=restaurant}, OUT={id=3, label=user}, upvotes=2, rated_at=Tue Nov 16 22:14:21 PKT 2021, downvotes=9, value=3}}
==>{rest={id=60, label=restaurant, name=restaurant7, location=karachi}, rev={id=72, label=review, IN={id=60, label=restaurant}, OUT={id=3, label=user}, upvotes=5, rated_at=Tue Nov 16 22:16:46 PKT 2021, downvotes=1, value=2}}
==>{rest={id=54, label=restaurant, name=restaurant5, location=karachi}, rev={id=66, label=review, IN={id=54, label=restaurant}, OUT={id=0, label=user}, upvotes=4.7, rated_at=Tue Nov 16 22:13:32 PKT 2021, downvotes=3, value=2}}

我怎样才能做到这一点？提前致谢。

Answer 1

您应该查看使用 project() 步骤（文档 here）来获取此类信息。如果没有重现图表的步骤，很难为您提供准确的查询，但它应该类似于以下查询：

  g.V(26).as("cui").
  inE("serves").
  outV().
  hasLabel("restaurant").
  has("location", "karachi").
  project('restaurant', 'reviews').
    by(elementMap()).
    by(
      inE("review").
      has('value', gte(2)).
      order().by("value", desc).
      fold())

Gremlin 将所有返回的边及其顶点分组

Gremlin group all returned edges with its vertices

graph-databases

gremlin

tinkerpop