具有字数限制的随机密码生成器

Question

我正在创建一个随机密码生成器。我想创建一个输入字段，其中密码长度只能是最小 8 和最大 16。如果用户输入的长度不是允许的长度，它会不断要求用户输入正确的密码长度。我使用 'return' 所以它 return 到 length = int(input('\nEnter the length of password: ')) ，但它在这里不起作用。我可以获得有关如何正确执行此操作的建议吗？

#input the length of password
#must be minimun 8 to maximun 16

length = int(input('\nEnter the length of password: '))

#if use enter less than 8 or more than 16 

if length < 8 :
        print('You password length is too short(must be more than 8 character)')
        return;
elif length > 16:
        print('You password length is too long(must be less than 17 character)')
        return;
else:
        print('You password length looks good')

Answer 1

改用内置 len 函数并使用 while 循环：

#input the length of password
#must be minimun 8 to maximun 16

#if use enter less than 8 or more than 16
l = False
while not l:
    length = input('\nEnter the length of password: ')
    if len(length) < 8 :
        print('You password length is too short(must be more than 8 character)')
        print(len(length), "is the length of your password")
    elif len(length) > 16:
            print('You password length is too long(must be less than 17 character)')
            print(len(length), "is the length of your password")
    else:
            print('You password length looks good')
            break

输出：

Enter the length of password: thisismorethan16characters
You password length is too long(must be less than 17 character)
26 is the length of your password

Enter the length of password: thisisgood
You password length looks good
>>>

此外，删除 int() 以便我们可以允许用户输入字符串，而您通常在函数中使用 return。 python.

中也没有使用 ;

Answer 2

the code will run till you enter a correct password. I declared a variable correct_pass set to false. with condition correct_pass == False in while loop when the user enters correct password the value of correct_pass is changed to True and hence it exits out of the loop and in other cases it value remains unchanged

correct_pass=False

while(correct_pass==False):
      length = input('\nEnter the length of password: ')
if len(length) < 8 :
    print('You password length is too short(must be more than 8 character)')
    correct_pass=False
elif len(length) < 8:
    print('You password length is too long(must be less than 17 character)')
    correct_pass=False
else:
    print('You password length looks good')
    correct_pass=True

Answer 3

您的代码基本上使用的是整数值，而不是用户输入的长度或整数个数。

假设我输入 9。

那么，您正在使用 If-elif-else 块。

如果长度（此时用户输入为 9）<8，打印“您的密码长度太短”。在我们的例子中，长度等于9，也小于17。所以我们满足条件。

但是如果我们输入，例如 0，2222。这显然比您的代码要求的值大得多。我希望我把你的错误弄清楚了。现在，修复方法是：

具有字数限制的随机密码生成器

Random password generator with words limit

python

password-generator

jupyter-notebook