xmlstarlet match/parsing 按属性而不是元素
xmlstarlet match/parsing by attribute instead of element
我有一个结构复杂的 XML 文件,我试图使用 xmlstartlet 从中解析一些值。我认为问题在于逻辑对象是由元素属性而不是实际元素名称标识的。
文件 test.xml 针对此示例进行了简化,如下所示:
<?xml version="1.0" encoding="utf-8"?>
<configDump>
<cluster top-level-assembly="XYZ12312312312">
</cluster>
<views>
<view status="ok" name="ABC">
<viewInitiators>
<viewInitiator id="ABCi1"></viewInitiator>
<viewInitiator id="ABCi2"></viewInitiator>
</viewInitiators>
<viewPorts>
<viewPort id="ABCp1"></viewPort>
<viewPort id="ABCp2"></viewPort>
</viewPorts>
<viewVolumes>
<viewVolume lun="1" id="ABCv1"></viewVolume>
<viewVolume lun="2" id="ABCv2"></viewVolume>
</viewVolumes>
</view>
<view status="ok" name="DEF">
<viewInitiators>
<viewInitiator id="DEFi1"></viewInitiator>
<viewInitiator id="DEFi2"></viewInitiator>
</viewInitiators>
<viewPorts>
<viewPort id="DEFp1"></viewPort>
<viewPort id="DEFp2"></viewPort>
</viewPorts>
<viewVolumes>
<viewVolume lun="1" id="DEFv1"></viewVolume>
<viewVolume lun="2" id="DEFv2"></viewVolume>
</viewVolumes>
</view>
</views>
</configDump>
我正在尝试使用如下字段生成输出:
<top-level-assembly>-<view-name>,<viewInitiator-ID>
当我运行以下内容时:
xmlstarlet sel -t \
-m //cluster \
--var sn=@top-level-assembly \
-m //views/view \
--var view=@name \
-m //views/view/viewInitiators/viewInitiator \
-v 'concat($sn,"-",$view,",",@id)' -n test.xml
我得到以下输出:
XYZ12312312312-ABC,ABCi1
XYZ12312312312-ABC,ABCi2
XYZ12312312312-ABC,DEFi1
XYZ12312312312-ABC,DEFi2
XYZ12312312312-DEF,ABCi1
XYZ12312312312-DEF,ABCi2
XYZ12312312312-DEF,DEFi1
XYZ12312312312-DEF,DEFi2
正如您所看到的,我正在获取每个“视图”下的所有“启动器”值,而不仅仅是 XML 中该结构中的那些值。我期待并希望得到:
XYZ12312312312-ABC,ABCi1
XYZ12312312312-ABC,ABCi2
XYZ12312312312-DEF,DEFi1
XYZ12312312312-DEF,DEFi2
对我做错了什么有什么想法吗?
Any thoughts on what I'm doing wrong?
-m
选项嵌套到 xsl:for-each
语句 - 因此您要为每个 view
请求所有 viewInitiator/@id
。要查看生成的 XSLT 代码,请在 -t
.
之前添加 -C
选项
可以通过以下方式生成所需的输出:
xmlstarlet sel -t \
--var sn='configDump/cluster/@top-level-assembly' \
-m '//viewInitiator' \
-v 'concat($sn,"-",../../@name,",",@id)' -n \
< file.xml
我有一个结构复杂的 XML 文件,我试图使用 xmlstartlet 从中解析一些值。我认为问题在于逻辑对象是由元素属性而不是实际元素名称标识的。
文件 test.xml 针对此示例进行了简化,如下所示:
<?xml version="1.0" encoding="utf-8"?>
<configDump>
<cluster top-level-assembly="XYZ12312312312">
</cluster>
<views>
<view status="ok" name="ABC">
<viewInitiators>
<viewInitiator id="ABCi1"></viewInitiator>
<viewInitiator id="ABCi2"></viewInitiator>
</viewInitiators>
<viewPorts>
<viewPort id="ABCp1"></viewPort>
<viewPort id="ABCp2"></viewPort>
</viewPorts>
<viewVolumes>
<viewVolume lun="1" id="ABCv1"></viewVolume>
<viewVolume lun="2" id="ABCv2"></viewVolume>
</viewVolumes>
</view>
<view status="ok" name="DEF">
<viewInitiators>
<viewInitiator id="DEFi1"></viewInitiator>
<viewInitiator id="DEFi2"></viewInitiator>
</viewInitiators>
<viewPorts>
<viewPort id="DEFp1"></viewPort>
<viewPort id="DEFp2"></viewPort>
</viewPorts>
<viewVolumes>
<viewVolume lun="1" id="DEFv1"></viewVolume>
<viewVolume lun="2" id="DEFv2"></viewVolume>
</viewVolumes>
</view>
</views>
</configDump>
我正在尝试使用如下字段生成输出:
<top-level-assembly>-<view-name>,<viewInitiator-ID>
当我运行以下内容时:
xmlstarlet sel -t \
-m //cluster \
--var sn=@top-level-assembly \
-m //views/view \
--var view=@name \
-m //views/view/viewInitiators/viewInitiator \
-v 'concat($sn,"-",$view,",",@id)' -n test.xml
我得到以下输出:
XYZ12312312312-ABC,ABCi1
XYZ12312312312-ABC,ABCi2
XYZ12312312312-ABC,DEFi1
XYZ12312312312-ABC,DEFi2
XYZ12312312312-DEF,ABCi1
XYZ12312312312-DEF,ABCi2
XYZ12312312312-DEF,DEFi1
XYZ12312312312-DEF,DEFi2
正如您所看到的,我正在获取每个“视图”下的所有“启动器”值,而不仅仅是 XML 中该结构中的那些值。我期待并希望得到:
XYZ12312312312-ABC,ABCi1
XYZ12312312312-ABC,ABCi2
XYZ12312312312-DEF,DEFi1
XYZ12312312312-DEF,DEFi2
对我做错了什么有什么想法吗?
Any thoughts on what I'm doing wrong?
-m
选项嵌套到 xsl:for-each
语句 - 因此您要为每个 view
请求所有 viewInitiator/@id
。要查看生成的 XSLT 代码,请在 -t
.
-C
选项
可以通过以下方式生成所需的输出:
xmlstarlet sel -t \
--var sn='configDump/cluster/@top-level-assembly' \
-m '//viewInitiator' \
-v 'concat($sn,"-",../../@name,",",@id)' -n \
< file.xml