ROLLUP的结果如何按每组总数排序

Question

所以我有以下查询产生以下结果：

    actname    | year     | tickets
---------------+----------+---------
 Join Division | 2016     |       2
 Join Division | 2018     |       2
 Join Division | 2020     |       3
 Join Division | Total    |       7 <<<
 QLS           | 2018     |       2
 QLS           | 2019     |       1
 QLS           | Total    |       3 <<<
 Scalar Swift  | 2017     |       3
 Scalar Swift  | 2018     |       1
 Scalar Swift  | 2019     |       1
 Scalar Swift  | Total    |       5 <<<
 The Selecter  | 2017     |       4
 The Selecter  | 2018     |       4
 The Selecter  | Total    |       8 <<<
 The Where     | 2016     |       1
 The Where     | 2017     |       3
 The Where     | 2018     |       5
 The Where     | 2020     |       4
 The Where     | Total    |      13 <<<
 ViewBee 40    | 2017     |       3
 ViewBee 40    | 2018     |       1
 ViewBee 40    | Total    |       4 <<<

我遇到的问题是我想对结果重新排序，使总计最低的组排在最前面，这样结果将如下所示：

    actname    | year     | tickets
---------------+----------+---------
 QLS           | 2018     |       2
 QLS           | 2019     |       1
 QLS           | Total    |       3 <<<
 ViewBee 40    | 2017     |       3
 ViewBee 40    | 2018     |       1
 ViewBee 40    | Total    |       4 <<<
 Scalar Swift  | 2017     |       3
 Scalar Swift  | 2018     |       1
 Scalar Swift  | 2019     |       1
 Scalar Swift  | Total    |       5 <<<
 Join Division | 2016     |       2
 Join Division | 2018     |       2
 Join Division | 2020     |       3
 Join Division | Total    |       7 <<<
 The Selecter  | 2017     |       4
 The Selecter  | 2018     |       4
 The Selecter  | Total    |       8 <<<
 The Where     | 2016     |       1
 The Where     | 2017     |       3
 The Where     | 2018     |       5
 The Where     | 2020     |       4
 The Where     | Total    |      13 <<<

我正在使用以下组获取结果：

GROUP BY actname, ROLLUP(year)

这就是把所有同名同年份的票数合并在一起。

如有需要，我可以提供完整的查询！

谢谢

Answer 1

使用 window 函数（在本例中为 sum()）您可以将值设置为组（组按 actname 列分区），所以现在每个组来自 actname 列，具有相同的值，作为它自己的行，其中 year='Total'.

然后简单地按新列排序，如下所示：

with t(actname, year, tickets) as (
VALUES
('Join Division','2016',2),
('Join Division','2018',2),
('Join Division','2020',3),
('Join Division','Total',7),
('QLS','2018',2),
('QLS','2019',1),
('QLS','Total',3 ),
('Scalar Swift','2017',3),
('Scalar Swift','2018',1),
('Scalar Swift','2019',1),
('Scalar Swift','Total',5 ),
('The Selecter','2017',4),
('The Selecter','2018',4),
('The Selecter','Total',8 ),
('The Where','2016',1),
('The Where','2017',3),
('The Where','2018',5),
('The Where','2020',4),
('The Where','Total',13 ),
('ViewBee 40','2017',3),
('ViewBee 40','2018',1),
('ViewBee 40','Total',4 )
)
SELECT * FROM (
    select *,  sum(case when year = 'Total' then tickets end) over(partition by actname) sm from t
) tt
ORDER BY sm, year

ROLLUP的结果如何按每组总数排序

How to order the result of ROLLUP by each groups total

postgresql

rollup