Java 如何在一个循环中遍历 2 个不同的数组

Question

我正在我的程序中创建一种方法，通过这些具有特定健康风险类别（低、中、高）的问号来判断用户是否有感染新冠肺炎的风险。预期的输出应该是，例如，如果用户在“a.fever”中输入“y”（是），答案将落在低（风险）的等效标记下，如果输入“n”，则继续下一个和依此类推，然后在回答完所有问题后，标记的累积数量（低、中高）将确定该人是否处于危险之中。（希望这能澄清代码的概述）

我正在尝试循环遍历 2 个具有相同长度的不同一维数组，结果在每个数组中应该只需要 1 个元素，但我在如何执行此操作方面遇到了真正的困难。下面是我的代码

    System.out.println(
            "1. Are you experiencing or did you have any of the following in the last 14 following in the last 14 days?");


    int low = 0, medium = 0, high = 0;

String[] no1SubQuestion = new String[10];
    no1SubQuestion[0] = "";
    no1SubQuestion[1] = "a. Fever";
    no1SubQuestion[2] = "b. Cough and/or Colds";
    no1SubQuestion[3] = "c. Body Pains";
    no1SubQuestion[4] = "d. Sore Throat";
    no1SubQuestion[5] = "e. Fatigue or Tiredness";
    no1SubQuestion[6] = "f. Headache";
    no1SubQuestion[7] = "g. Diarrhea";
    no1SubQuestion[8] = "h. Loss of Taste or Smell";
    no1SubQuestion[9] = "i. Difficulty of Breathing";

    int[] no1SubQuestHealthRisk = new int[10];
    no1SubQuestHealthRisk[0] = 0;
    no1SubQuestHealthRisk[1] = low;
    no1SubQuestHealthRisk[2] = medium;
    no1SubQuestHealthRisk[3] = high;
    no1SubQuestHealthRisk[4] = high;
    no1SubQuestHealthRisk[5] = high;
    no1SubQuestHealthRisk[6] = high;
    no1SubQuestHealthRisk[7] = high;
    no1SubQuestHealthRisk[8] = high;
    no1SubQuestHealthRisk[9] = high;

    for (int i = 0; i < no1SubQuestion.length; i++) {
        for (int j = 0; j < no1SubQuestHealthRisk.length; j++) {
            try {
                System.out.println(no1SubQuestion[i]);
                input.nextLine();
                System.out.printf("(Enter \"Y\" if YES, \"N\" if NO only)\n>> ");
                String answer = input.nextLine();

                if (!answer.equalsIgnoreCase("y") & !answer.equalsIgnoreCase("n")) {
                    throw new InputMismatchException("invalid input");
                }

                boolean isYes = answer.equalsIgnoreCase("y");

                if (!isYes) {
                    continue;
                }

                no1SubQuestHealthRisk[j] += 1;
            } catch (InputMismatchException e) {
                System.out.println("Error!!! (Please enter \"Y\" if YES, \"N\" if NO only)");
                input.nextLine();
            }
        }
    }

        if (high > 0) {
        result = "HIGH";
    } else if (medium > 0 && high == 0) {
        result = "MEDIUM";
    } else if ((low == 1 || low == 2) && (medium == 0 && high == 0)) {
        result = "LOW";
    } else {
        result = "NO";
    }
    return result;

结果应在 no1SubQuestion 数组上打印一个元素，然后在用户输入后，答案应存储到 no1SubQuestHealthRisk 数组中的等效整数（低、中、高）

现在使用给定的代码输出是这样的

但我正在尝试这样做

Answer 1

您的问题索引以 1 开头，因此应以 i=1 开头。
你不需要 2 个数组，一个就可以了。
而不是第二个 for 循环，while 循环会做得更好，因为它只是为了获得有效输入。

int low = 0, medium = 0, high = 0;
for (int i = 1; i < no1SubQuestion.length; i++) {
    System.out.println(no1SubQuestion[i]);
    System.out.printf("(Enter \"Y\" if YES, \"N\" if NO only)\n>> ");
    while(true) {
        try {
            String answer = input.nextLine();

            if (!answer.equalsIgnoreCase("y") & !answer.equalsIgnoreCase("n")) {
                throw new InputMismatchException("invalid input");
            }

            boolean isYes = answer.equalsIgnoreCase("y");
            //in the answer is no, no need to increment.
            if (!isYes) {
                break;
            }
            //increment the respective risk categories.
            if(i==1)
                low++;
            else if(i==2)
                medium++;
            else 
                high++;
            break;
        } catch (InputMismatchException e) {
            System.out.println("Error!!! (Please enter \"Y\" if YES, \"N\" if NO only)");
        }
    }
}
if (high > 0)
    result = "HIGH";
else if (medium > 0)
    result = "MEDIUM";
else if (low > 0)
    result = "LOW";
else
    result = "NO";
return result;

Java 如何在一个循环中遍历 2 个不同的数组

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