shutil.copy2 只复制一个文件并停止，而不是从循环中复制整个文件

Question

我有两个具有 1 个功能的代码（从 src 文件夹中复制文件，这些文件存在于单元格 product_number 中）

问题是代码只复制了 1 个文件，程序没有完成就停止了复制。

我该如何解决？

def copy_images(excel_path):
    src = r'D:\src_img'
    destination_folder = r'D:\dest_img'

    copy_file = openpyxl.load_workbook(excel_path)
    data_list = copy_file.active

    for path, subdirs, files in os.walk(src):
        for name in files:
            filename = os.path.join(path, name)
            for row in range(2, data_list.max_row + 1):
                product_number = str(data_list.cell(row, 1).value)

                if product_number in filename:
                    full_dest_path = os.path.join(destination_folder, filename.lstrip(src).lstrip('/'))

                    dirname = os.path.dirname(full_dest_path)
                    if not os.path.exists(dirname):
                        os.makedirs(dirname)

                        shutil.copy2(filename, full_dest_path)


def update_images(excel_path):
    src = r'D:\src_img'
    dest = r'D:\dest_img'

    copy_file = openpyxl.load_workbook(excel_path)
    data_list = copy_file.active

    for path, subdirs, files in os.walk(src):
        for name in files:
            filename = os.path.join(path, name)
            for row in range(2, data_list.max_row + 1):
                product_number = str(data_list.cell(row, 1).value)

                if product_number in filename:
                    if not os.path.exists(dest):
                        os.makedirs(dest)

                        shutil.copy2(filename, os.path.join(dest, name))

Answer 1

将 shutil.copy2() 行缩进到与 if 语句相同的级别，因此无论目录是否存在，它们都会被执行。

shutil.copy2 只复制一个文件并停止，而不是从循环中复制整个文件

shutil.copy2 is copying only one file and stops, instead copying the whole files from loop

python

shutil