T-SQL,在视图中重复相同的标量子查询性能
T-SQL, repeated same scalar subquery performance in views
下面是一个简单的查询,用于检索学生及其考试成绩。同一个学生可以多次参加同一个考试。子查询检索每个学生的最新考试成绩。如您所见,X 行(检索最新的考试 ID)在每一行的每个子查询中完全相同。如何存储或缓存X行的结果以防止每行执行三次?
我不能为此任务使用存储过程或函数,它必须是一个 VIEW 以进行额外的过滤。
SELECT S.*,
(
SELECT COUNT(*) FROM ExamAnswers WHERE
IsCorrectAnswer IS NOT NULL AND
IsCorrectAnswer = 1 AND
ExamID =
(SELECT TOP(1) ID FROM Exams E WHERE E.StudentID = S.ID ORDER BY ID DESC) --Line X
) CorrectAnswerCount,
(
SELECT COUNT(*) FROM ExamAnswers EA WHERE
EA.IsCorrectAnswer IS NOT NULL AND
EA.IsCorrectAnswer = 0 AND
EA.ExamID =
(SELECT TOP(1) ID FROM Exams E WHERE E.StudentID = S.ID ORDER BY ID DESC) --Line X
) WrongAnswerCount,
(
SELECT COUNT(*) FROM ExamAnswers WHERE
IsCorrectAnswer IS NULL AND
ExamID =
(SELECT TOP(1) ID FROM Exams E WHERE E.StudentID = S.ID ORDER BY ID DESC) --Line X
) UnansweredQuestionCount
FROM Students S
你可以这样做
SELECT S.*,
CA.*
FROM Students S
CROSS APPLY (SELECT SUM(CASE WHEN IsCorrectAnswer = 1 THEN 1 ELSE 0 END) AS CorrectAnswerCount,
SUM(CASE WHEN IsCorrectAnswer = 0 THEN 1 ELSE 0 END) AS WrongAnswerCount,
SUM(CASE WHEN IsCorrectAnswer IS NULL THEN 1 ELSE 0 END) AS UnansweredQuestionCount
FROM ExamAnswers EA
WHERE EA.ExamID = (SELECT TOP(1) ID
FROM Exams E
WHERE E.StudentID = S.ID
ORDER BY ID DESC)) CA
这种方法怎么样:
WITH
T AS
(
SELECT Student_id,
SUM(CASE IsCorrectAnswer WHEN 1 THEN 1 END) AS COUNT_TRUE,
SUM(CASE IsCorrectAnswer WHEN 0 THEN 1 END) AS COUNT_FALSE,
SUM(CASE WHEN IsCorrectAnswer IS NULL THEN 1 END) AS COUNT_UNKNOWN
FROM ExamAnswers AS EA
WHERE EA.ExamID = (SELECT MAX(ID)
FROM Exams E
WHERE E.StudentID = S.ID)
GROUP BY Student_id
)
SELECT S.*, COUNT_TRUE, COUNT_FALSE, COUNT_UNKNOWN
FROM Students AS S
JOIN T ON S.ID = T.Student_id
下面是一个简单的查询,用于检索学生及其考试成绩。同一个学生可以多次参加同一个考试。子查询检索每个学生的最新考试成绩。如您所见,X 行(检索最新的考试 ID)在每一行的每个子查询中完全相同。如何存储或缓存X行的结果以防止每行执行三次? 我不能为此任务使用存储过程或函数,它必须是一个 VIEW 以进行额外的过滤。
SELECT S.*,
(
SELECT COUNT(*) FROM ExamAnswers WHERE
IsCorrectAnswer IS NOT NULL AND
IsCorrectAnswer = 1 AND
ExamID =
(SELECT TOP(1) ID FROM Exams E WHERE E.StudentID = S.ID ORDER BY ID DESC) --Line X
) CorrectAnswerCount,
(
SELECT COUNT(*) FROM ExamAnswers EA WHERE
EA.IsCorrectAnswer IS NOT NULL AND
EA.IsCorrectAnswer = 0 AND
EA.ExamID =
(SELECT TOP(1) ID FROM Exams E WHERE E.StudentID = S.ID ORDER BY ID DESC) --Line X
) WrongAnswerCount,
(
SELECT COUNT(*) FROM ExamAnswers WHERE
IsCorrectAnswer IS NULL AND
ExamID =
(SELECT TOP(1) ID FROM Exams E WHERE E.StudentID = S.ID ORDER BY ID DESC) --Line X
) UnansweredQuestionCount
FROM Students S
你可以这样做
SELECT S.*,
CA.*
FROM Students S
CROSS APPLY (SELECT SUM(CASE WHEN IsCorrectAnswer = 1 THEN 1 ELSE 0 END) AS CorrectAnswerCount,
SUM(CASE WHEN IsCorrectAnswer = 0 THEN 1 ELSE 0 END) AS WrongAnswerCount,
SUM(CASE WHEN IsCorrectAnswer IS NULL THEN 1 ELSE 0 END) AS UnansweredQuestionCount
FROM ExamAnswers EA
WHERE EA.ExamID = (SELECT TOP(1) ID
FROM Exams E
WHERE E.StudentID = S.ID
ORDER BY ID DESC)) CA
这种方法怎么样:
WITH
T AS
(
SELECT Student_id,
SUM(CASE IsCorrectAnswer WHEN 1 THEN 1 END) AS COUNT_TRUE,
SUM(CASE IsCorrectAnswer WHEN 0 THEN 1 END) AS COUNT_FALSE,
SUM(CASE WHEN IsCorrectAnswer IS NULL THEN 1 END) AS COUNT_UNKNOWN
FROM ExamAnswers AS EA
WHERE EA.ExamID = (SELECT MAX(ID)
FROM Exams E
WHERE E.StudentID = S.ID)
GROUP BY Student_id
)
SELECT S.*, COUNT_TRUE, COUNT_FALSE, COUNT_UNKNOWN
FROM Students AS S
JOIN T ON S.ID = T.Student_id