如何使用动态数组删除二维数组 C++ 中的列？

Question

我想删除二维数组中最大整数的列，我是这样做的，但是为什么要删除列和行？我可以修复它并只删除列吗？任务是用删除命令完成的，但现在我认为这是不可能的

#include <iostream>

using namespace std;

int main()
{

int row = 3, col = 3;
int** arr = new int* [row];
for(int i = 0; i < row; i++){
    arr[i] = new int[col];
}
for(int i = 0; i < row; i++){
    for(int j = 0; j < col; j++) {
        cin >> arr[i][j];
    }
}
for(int i = 0; i < row; i++){
    for(int j = 0; j < col; j++) {
        cout << arr[i][j] << " ";
    }
    cout << endl;
}
    cout << " ------------- " << endl;

int max = 0, index = 0;
for(int i =0; i < row; i++){
    for(int j = 0; j < col; j++){
        if(arr[i][j] > max){
            max = arr[i][j];
            index = i;
        }
    }
}
delete [] arr[index];
int** tmp = new int*[index - 1];
int tmpI = 0;
for(int i = 0; i < col; i++){
    if(i != index){
        tmp[tmpI++] = arr[i];
    }
}
delete [] arr;
arr = tmp;
col = col - 1;

for(int i = 0; i < row; i++){
    for(int j = 0; j < col; j++) {
        cout << arr[i][j] << " ";
    }
    cout << endl;
}

}

Answer 1

对于初学者来说，变量索引设置为行号

index = i;

然后删除这一行

delete [] arr[index];

但是您要删除的是一列而不是一行。所以这段代码没有意义。

另外你搜索的最大元素不正确。如果用户将输入所有负值，那么最大值将等于 0，尽管数组中不存在具有该值的元素。

在此声明中

int** tmp = new int*[index - 1];

您分配了一个数组，其行数比原始数组中的行数少一。此外，如果索引等于 0，则分配了非常大的内存范围。

这条语句

delete [] arr;

产生内存泄漏。

看来你需要的是下面这样的东西

#include <iostream>

int main() 
{
    size_t row = 3, col = 3;
    
    int **arr = new int * [row];

    for ( size_t i = 0; i < row; i++ )
    {
        arr[i] = new int[col];
    }
    
    for ( size_t i = 0; i < row; i++ )
    {
        for ( size_t j = 0; j < col; j++ ) 
        {
            std::cin >> arr[i][j];
        }
    }
    
    for ( size_t i = 0; i < row; i++ )
    {
        for ( size_t j = 0; j < col; j++ ) 
        {
            std::cout << arr[i][j] << " ";
        }
        std::cout << std::endl;
    }
    
    std::cout << "------------- " << std::endl;
    
    size_t max_i = 0, max_j = 0;
    
    for ( size_t i = 0; i < row; i++ )
    {
        for ( size_t j = 0; j < col; j++ )
        {
            if ( arr[max_i][max_j] < arr[i][j] )
            {
                max_i = i; max_j = j;
            }
        }
    }
    
    int **tmp = new int*[row];
    for ( size_t i = 0; i < row; i++ )
    {
        tmp[i] = new int[col-1];
    }
    
    for ( size_t i = 0; i < row; i++ )
    {
        for ( size_t j = 0, k = 0; j < col; j++ )
        {
            if ( j != max_j ) tmp[i][k++] = arr[i][j];
        }
    }
    
    for ( size_t i = 0; i < row; i++ )
    {
        delete [] arr[i];
    }
    
    delete [] arr;
    
    arr = tmp;
    
    --col;
    
    for ( size_t i = 0; i < row; i++ )
    {
        for ( size_t j = 0; j < col; j++ ) 
        {
            std::cout << arr[i][j] << " ";
        }
        std::cout << std::endl;
    }
    
    for ( size_t i = 0; i < row; i++ )
    {
        delete [] arr[i];
    }
    
    delete [] arr;
    
    return 0;
}

程序输出可能看起来像

1 2 3 
6 5 4 
7 9 8 
 ------------- 
1 3 
6 4 
7 8

Answer 2

这里有一个备选建议：您正在以 row x column 格式存储数据。如果更改为 column x row 格式，则删除列会变得更容易。我还制作了一个辅助函数来打印矩阵，并将输入循环和找到最大值的循环结合起来。

#include <iostream>
#include <iomanip>
#include <cstdlib>  // for rand
#include <climits>

using namespace std;

void print_matrix(int** arr, int rows, int columns)
{
    for(int row = 0; row < rows; row++){
        for(int col = 0; col < columns; col++) {
            cout << setw(2) << arr[col][row] << " ";
        }
        cout << "\n";
    }
}

int main()
{
    srand(time(nullptr));  // For testing
    
    int rows = 3, columns = 3;
    
    // Create the matrix
    int** arr = new int *[columns];
    for (int col = 0; col < columns; col++) {
        arr[col] = new int[rows];
    }
    
    // Input values - finding max, too
    int max_value = INT_MIN, max_value_column = -1;
    for (int row = 0; row < rows; row++) {
        for (int col = 0; col < columns; col++) {
            //cin >> arr[col][row];
            arr[col][row] = rand() % 50;    // Using rand for testing.
            if (arr[col][row] > max_value) {
                max_value = arr[col][row];
                max_value_column = col;
            }
        }
    }   
    print_matrix(arr, rows, columns);
    cout << " ------------- " << endl;

    // Delete the column with max
    delete [] arr[max_value_column];
    columns--;
    // Shift columns to the right of the deleted column left one
    for (int col = max_value_column; col < columns; col++) {
        arr[col] = arr[col + 1];
    }
    print_matrix(arr, rows, columns);

    return 0;
}

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