如何 return 具有给定值的对象？

Question

我正在做一个搜索过滤器。我需要 return 包含用户给定演员的整个对象。我可以找到演员，但我不确定如何 return 演员所在的对象。

JSON 文件:

{
    "title": "American Assassin",
    "year": 2017,
    "cast": [
        "Dylan O'Brien",
        "Michael Keaton",
        "Sanaa Lathan",
        "Shiva Negar",
        "Taylor Kitsch"
    ],
    "genres": []
},
{
    "title": "Mother!",
    "year": 2017,
    "cast": [
        "Jennifer Lawrence",
        "Javier Bardem",
        "Michelle Pfeiffer",
        "Domhnall Gleeson",
        "Ed Harris",
        "Kristen Wiig"
    ],
    "genres": []
}

我的过滤函数：

checkCast(allMovies) {
      return filter(allMovies, (movie) => {
        const actor = filter(movie.cast, (actor) => {
          return actor.toLowerCase().includes(this.search.cast.toLowerCase())
        })
        console.log(actor)
        return actor
      });
    }

希望一切都清楚。

Answer 1

您可以使用 array#find 和 array#includes 来检查电影演员表是否包含演员。

const movies = [{ "title": "American Assassin", "year": 2017, "cast": [ "Dylan O'Brien", "Michael Keaton", "Sanaa Lathan", "Shiva Negar", "Taylor Kitsch" ], "genres": [] }, { "title": "Mother!", "year": 2017, "cast": [ "Jennifer Lawrence", "Javier Bardem", "Michelle Pfeiffer", "Domhnall Gleeson", "Ed Harris", "Kristen Wiig" ], "genres": [] }],
      actor = 'Ed Harris',
      movie = movies.find(({cast}) => cast.includes(actor));
console.log(movie);

您也可以将演员和演员姓名转换为小写，以便使用 array#find 和 array#some 进行比较。

const movies = [{ "title": "American Assassin", "year": 2017, "cast": [ "Dylan O'Brien", "Michael Keaton", "Sanaa Lathan", "Shiva Negar", "Taylor Kitsch" ], "genres": [] }, { "title": "Mother!", "year": 2017, "cast": [ "Jennifer Lawrence", "Javier Bardem", "Michelle Pfeiffer", "Domhnall Gleeson", "Ed Harris", "Kristen Wiig" ], "genres": [] }],
      actor = 'ed harris',
      movie = movies.find(({cast}) => cast.some(member => member.toLowerCase() === actor.toLowerCase()));
console.log(movie);

Answer 2

您需要通过在 case 数组中查找演员来过滤 allMovies 数组。如果找到匹配的演员，请使用 Array.some()（或 lodash _.some()）到 return true。

const search = { cast: 'bardem' };

function checkCast(allMovies) {
  return allMovies.filter(movie =>
    movie.cast.some(actor =>
      actor.toLowerCase().includes(search.cast.toLowerCase())
    )
  );
}

const allMovies = [{"title":"American Assassin","year":2017,"cast":["Dylan O'Brien","Michael Keaton","Sanaa Lathan","Shiva Negar","Taylor Kitsch"],"genres":[]},{"title":"Mother!","year":2017,"cast":["Jennifer Lawrence","Javier Bardem","Michelle Pfeiffer","Domhnall Gleeson","Ed Harris","Kristen Wiig"],"genres":[]}]

const result = checkCast(allMovies)

console.log(result)

如何 return 具有给定值的对象？

How to return an object with a given value?

javascript

lodash

vue.js