括号中的 Word VBA 宏

Word VBA macro on parentheticals

我一直在使用以下宏将括号中的项目提取到 word 中的评论中:

'
' CommentBubble Macro
'
'
Dim myRange As Range
Set myRange = ActiveDocument.Content
searchtext = "\(*\)"

With myRange.Find
    .MatchWildcards = True
    Do While .Execute(findText:=searchtext, Forward:=True) = True
      If Len(myRange.Text) > 4 Then
        ActiveDocument.Comments.Add myRange, myRange.Text
        myRange.Text = ""
      End If
    Loop
 End With
End Sub

我将文本长度设置为 > 4 的原因是因为这些是法律文件,我不想在以下条件下隔离具有类似 " 的字符串:(i) 条件 1,(ii) ) 条件 2 等"

但是,上面的代码中断了一段文本:

This is sample text (with some additional text) that does stuff (with more stuff) and represents 39.4% of shares on the effective date (before giving effect, with some conditions such as ( some stuff (i) and some stuff (ii) with final stuff) and more final stuff) which is subject to  (some conditions here) and conclude here. 

如果你运行这个你会得到以下结果:

This is sample text  that does stuff  and represents 39.4% of shares on the effective date  and some stuff (ii) with final stuff) and more final stuff) which is subject to   and conclude here. 

如您所见,嵌套的括号引起了一些麻烦。有什么建议吗?

谢谢!

您正在尝试匹配括号,这在 Word 中是一项艰巨且吃力不讨好的任务,因为 Word 仅将左括号和右括号视为单独的字符,而不会按单词自动匹配。下面的代码找到匹配的括号,消除尾随空格,处理没有括号的情况,并在出现不平衡错误时出错。我留在调试语句中,以便您可以取消注释它们以查看发生了什么。

Option Explicit

Public Sub ttest()

    Dim myRange As Word.Range
    Set myRange = ActiveDocument.StoryRanges(wdMainTextStory)
    myRange.Collapse direction:=wdCollapseStart
    
    
    Set myRange = NextParenRange(myRange)
    
    Do Until myRange Is Nothing
    
        DoEvents
        
        Debug.Print myRange.Text
        Dim myDupRange As Word.Range
        Set myDupRange = myRange.Duplicate
        myRange.Collapse direction:=wdCollapseEnd
        If myDupRange.Characters.Last.Next.Text = " " Then myDupRange.MoveEnd Count:=1
        myDupRange.Delete
        Set myRange = NextParenRange(myRange)
        
    
    Loop
    
End Sub

Public Function NextParenRange(ByVal ipRange As Word.Range) As Word.Range

    Const OpenP As String = "("
    Const CloseP As String = ")"
    
    Dim myRange As Word.Range
    Set myRange = ipRange.Duplicate
    
    'If myRange.Start <> myRange.End Then myRange.Collapse direction:=wdCollapseStart
    
    'exit if no parentheses exist
    'Debug.Print myRange.Start
    If myRange.MoveUntil(cset:=OpenP) = 0 Then
    
        Set NextParenRange = Nothing
        Exit Function
        
        
    Else
    
        'Debug.Print myRange.Start
        Dim myParenCount As Long
        myParenCount = 1
        myRange.MoveEnd Count:=1

    End If
    
    
    Do Until myParenCount = 0
    
        ' allows VBA to respond to a break key press
        DoEvents
        
        ' if we run out of parentheses before we get back to zero then flag an error
        If myRange.MoveEndUntil(cset:=OpenP & CloseP) = 0 Then
        
            VBA.Err.Raise 17, "Unbalanced parentheses in document"
            
            
        End If
        
        myRange.MoveEnd Count:=1
        'Debug.Print myRange.Characters.Last.Text
        'Debug.Print myRange.Characters.Last.Next.Text
        myParenCount = myParenCount + IIf(myRange.Characters.Last.Text = OpenP, 1, -1)
        
    
    Loop
    
    Set NextParenRange = myRange.Duplicate
    
End Function